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yKpoI14uk [10]
3 years ago
14

If y = ax² + bx + c is the general form of a quadratic function, what is y = a(x - h)² + k? *

Mathematics
1 answer:
Ierofanga [76]3 years ago
3 0

Step-by-step explanation:

it is the vertex form.

remember, (h, k) is the vertex point.

the vertex being the point of the (quadratic) parabola, where the curve turns around.

depending on the orientation of the parabola (vertex up or vertex down) as defined by the sign of a, this is either the minimum or the maximum of the curve.

so, the first a. is correct.

and so is the second a., as they play an important role when completing the square and hence finishing the transformation.

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At a basketball game, a vendor sold a combined total of 197 sodas and hot dogs. The number of hot dogs sold was 41 less than the
Sedbober [7]

Answer:

58 hotdogs and 139 sodas were sold

3 0
2 years ago
URGENT!!!
Mrac [35]

Answer:

You can do this without the calculator

115 grams

after 1 half-life = 115 / 2 = 57.5 grams

after 2 half-lives = 28.75 grams

after 3 half-lives = 14.375 grams

after 4 half-lives = 7.1875 grams

after 5 half-lives = 3.59375 grams

after 6 half-lives = 1.796875 grams

 

Step-by-step explanation:


6 0
3 years ago
A rectangular garden is fenced on three sides with a wall forming on the fourth side. The total length of the fence is 120m. The
creativ13 [48]

Answer:

20m by 80m

Step-by-step explanation:

Let the dimension of the garden be x by y

The garden is fenced on three sides with a perimeter of 120m

Perimeter of the three sides = 2x+y

Therefore:

  • 2x+y=120

The Area of the garden = 1600m^2

  • xy=1600

From the first equation, y=120-2x

Substitute  y=120-2x into xy=1600

xy=1600

x(120-2x)=1600

120x-2x^2=1600\\2x^2-120x+1600=0\\2x^2-80x-40x+1600=0\\2x(x-40)-40(x-40)=0\\(2x-40)(x-40)=0\\2x-40=0\: x-40=0\\x=20 \: or \: x=40

Recall,

xy=1600

When x=20, 20y=1600===>y=80

When x=40, 40y=1600===>y=40

So we have the pair (20,80) and (40,40).

However since we are told that the garden is rectangular, we pick the dimension with unequal sides.

The dimension of the garden is 20m by 80m.

4 0
3 years ago
(+)=(+) what is the property
AfilCa [17]
There’s nothing there
3 0
3 years ago
A boat is pulled into a dock by means of a rope attached to a pulley on the dock. The rope is attached to the boat 10 feet below
Tresset [83]

Answer: 101.6 ft/min

Step-by-step explanation:

let x be the horizontal distance to the dock. And the rope is attached to the boat 10 feet below the pulley

Using pythagorean theorem

x^2=R^2-10^2

where R is rope length to the pulley.

Differentiates with respect to time t

2x dx/dt=2RdR/dt

Xdx/dt = RdR/dt ...... (1)

If the boat be approaching the dock when 125 ft of rope is out

This is R = 125ft

Using pythagorean theorem again

X^2 = R^2 - 10^2

X^2 = 125^2 - 10^2

X^2 = 15525

X = 124.6 ft

The rate the boat be approaching the dock = dx/dt

While

the rope is pulled through the pulley at a rate of 20 ft/min = dR/dt

Solve for dx/dt when R is 125, x= 124.6 and dR/dt= 20ft/min

Substitute all in equation 1

124.6 dx/dt = 125 × 20

dx/dt = 2500/124.6

dx/dt = 101.6 ft/min

4 0
3 years ago
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