3/4 = 6/8 = 9/12
4/5 = 8/10 = 12/15
The question might have some mistake since there are 2 multiplier of t. I found a similar question as follows:
The population P(t) of a culture of bacteria is given by P(t) = –1710t^2+ 92,000t + 10,000, where t is the time in hours since the culture was started. Determine the time at which the population is at a maximum. Round to the nearest hour.
Answer:
27 hours
Step-by-step explanation:
Equation of population P(t) = –1710t^2+ 92,000t + 10,000
Find the derivative of the function to find the critical value
dP/dt = -2(1710)t + 92000
= -3420t + 92000
Find the critical value by equating dP/dt = 0
-3420t + 92000 = 0
92000 = 3420t
t = 92000/3420 = 26.90
Check if it really have max value through 2nd derivative
d(dP)/dt^2 = -3420
2nd derivative is negative, hence it has maximum value
So, the time when it is maximum is 26.9 or 27 hours
Answer:
Step-by-step explanation:
For p'(4):
For q'(8):
Answer:
A
Step-by-step explanation:
(I hope it is right)
XY = xZ
85b + 83 = 91b - 283
Subtract 85b from both sides:
83 = 6b - 283
Add 283 to both sides:
6b = 366
Divide both sides by 6:
B = 61
Now replace b with 61 and solve for the length:
85(61) + 83
5185 + 83 = 5268
The length is 5,268
