Uhm, I'm pretty new to expanded form but I think it's something like:
(3 × 1/10) + (1 × 1/100) + (6 × 1/1000)
You can also write it as:
0.3 + 0.01 + 0.006
Let me know if you need working or anything!
The height of the fifth bounce
80x65%x65%x65%x65%x65%
=9.282325 cm
Answer:
Step-by-step explanation:
Givens
Let the width = x
Let the length = x + 5
Equation
2w + 2W = P
Solution
2x + 2(x + 5) = 192 Remove the brackets <=== Answer
2x + 2x + 10 = 192 Combine like terms
4x + 10 = 192 Subtract 10 from both sides
4x = 192 - 10
4x = 182 Divide by 4
4x/4 = 182/4
x = 45.5
1. Introduction. This paper discusses a special form of positive dependence.
Positive dependence may refer to two random variables that have
a positive covariance, but other definitions of positive dependence have
been proposed as well; see [24] for an overview. Random variables X =
(X1, . . . , Xd) are said to be associated if cov{f(X), g(X)} ≥ 0 for any
two non-decreasing functions f and g for which E|f(X)|, E|g(X)|, and
E|f(X)g(X)| all exist [13]. This notion has important applications in probability
theory and statistical physics; see, for example, [28, 29].
However, association may be difficult to verify in a specific context. The
celebrated FKG theorem, formulated by Fortuin, Kasteleyn, and Ginibre in
[14], introduces an alternative notion and establishes that X are associated if
∗
SF was supported in part by an NSERC Discovery Research Grant, KS by grant
#FA9550-12-1-0392 from the U.S. Air Force Office of Scientific Research (AFOSR) and
the Defense Advanced Research Projects Agency (DARPA), CU by the Austrian Science
Fund (FWF) Y 903-N35, and PZ by the European Union Seventh Framework Programme
PIOF-GA-2011-300975.
MSC 2010 subject classifications: Primary 60E15, 62H99; secondary 15B48
Keywords and phrases: Association, concentration graph, conditional Gaussian distribution,
faithfulness, graphical models, log-linear interactions, Markov property, positive
Answer:
3m-25>68
Step-by-step explanation:
Your Welcome
Btw- I didn't write a step by step explanation cause it doesn't need one.