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3 years ago

It have 72 chicken and 4ó3 dogs how many are they in altogether

Mathematics

2 answers:

Alborosie3 years ago

8 0

72 chicken and 4ó3 dogs come to 535 animals altogether.

Alexus [3.1K]3 years ago

8 0

403+72 = 505! Hope this helps

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Please help me with this

MissTica

Answer:

For the question on the right, I assume b is the exponential factor, or growth factor.

Step-by-step explanation:

Linear:

$Y=aX + b\\(X, Y) = (0, 15) => b = 15\\(X,Y) = (1, 12) => a = -3\\Y = -3X + 15$

You can find the equation by using two points and the equation for a line.

Exponential:

$Y = a^{bX+c}\\(X, Y) = (0, 81) => a^{c} = 81 => a^{c} = 3^{4} => a=3, c=4\\(X, Y) = (1, 27) => a^{b+c} = 27 => a^{b}a^{c} = 27 => a^{b} = \frac{27}{81} = \frac{1}{3} => b=-1\\Y = 3^{-X+4}$

6 0

2 years ago

What conclusion can be made ?

Zina [86]

Step-by-step explanation:

CD is congruent to EB

CD≈EB

5 0

3 years ago

32 ft2 of carpet costs $477.84. What is the cost of the carpet per square foot?

Genrish500 [490]

Divide the total amount of money by the total amount of feet.

477.84/32 = $14.93

hope this helps :)

3 0

3 years ago

In order to evaluate the performance of the artificial pancreas, a researcher randomly draw 5 rats as a control group, and draw

forsale [732]

Answer: 42.190

Step-by-step explanation:

From the question, the population variances are not equal. The calculation has been attached in the picture below.

The answer is 42.190 to 3 decimal places.

4 0

3 years ago

Help please?

Alla [95]

$\bf \begin{array}{clclll}
3^{1001}&\qquad &4^{1002}\\
\uparrow &&\uparrow \\
a&&b
\end{array}\\\\
-----------------------------\\\\
(a+b)^2-(a-b)^2\implies (a^2+2ab+b^2)-(a^2-2ab+b^2)
\\\\\\
a^2+2ab+b^2-a^2+2ab-b^2\implies 2ab+2ab\implies 4ab
\\\\\\
now\qquad 4(3^{1001})(4^{1002})=k12^{1001}\qquad 
\begin{cases}
12^{1001}\\
(4\cdot 3)^{1001}\\
4^{1001}\cdot 3^{1001}
\end{cases}$

$\bf \\\\\\
4(3^{1001})(4^{1002})=k(4^{1001}\cdot 3^{1001})\implies \cfrac{4(3^{1001})(4^{1002})}{4^{1001}\cdot 3^{1001}}=k
\\\\\\
4\cdot \cfrac{3^{1001}}{3^{1001}}\cdot \cfrac{4^{1002}}{4^{1001}}=k\implies 4\cdot 4^{1002}4^{-1001}=k\impliedby 
\begin{array}{llll}
\textit{same base}\\
\textit{add the}\\
exponents
\end{array}
\\\\\\
4\cdot 4^{1002-1001}=k\implies 4\cdot 4^1=k\implies 16=k$

6 0

3 years ago