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Marianna [84]
3 years ago
6

Is 3/7 and 10/21 proportional ? 15 points

Mathematics
1 answer:
Ksenya-84 [330]3 years ago
4 0

Answer:

NOT proportional.

Step-by-step explanation:

Get a common denominator of 21 by multiplying 7 and 3 by 3.

\frac{3}{7}(\frac{3}{3})=\frac{9}{21}

When both fractions have the same denominator, their numerators are different. Therefore, they are NOT proportional.

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Graph the function represented in the table on the coordinate plane.
Lena [83]

Step-by-step explanation:

We are given the co-ordinates,

x : -2, -1, 0, 1, 2

y : 8, 5, 2, -1, -4

According to the graph, we see that this function represents a straight line.

The general form of the straight line is y = mx + c, where m is the slope and c is the y-intercept.

So, taking any two points we will find the equation of the straight line.

Consider, (0,2) and (1, -1). Now, slope is given by,

m = \frac{-1-2}{1-0}

i.e. m = -3

Now, we will find the y-intercept of this equation using (0,2) and m = -3,

i.e. y = -3x + c

i.e. 2 = c

Hence, the equation of the straight line is y = -3x + 2.

6 0
4 years ago
Which digit is in the hundredth place in the following number: 234.567 *​
iVinArrow [24]

Answer:

4 because digits are counted before decimal.

8 0
2 years ago
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Sergeu [11.5K]

Answer:

X = 36/17

y = -8/17

Step-by-step explanation:

Since they both equal y, you could use them equal to each other.

(5/2)x-4=(-1/3)x+2

Then solve for x by combining like terms. X should be 36/17. Plug in x to find y in one of the equations. I will use the top one. (5/3)(36/17)-4=y. That should simplify down to (60/17)-4=y. Y would finally equal -(8/17).

6 0
3 years ago
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A roulette wheel has the numbers 1 through 36, 0, and 00. A bet on four numbers pays 8 to 1 (that is, if you bet $1 and one of t
Natasha_Volkova [10]

Answer:

Lose $0.05

Step-by-step explanation:

There are 38 possible spots on the roulette wheel (numbers 1 to 36, 0 and 00).

If the player can choose four numbers on single $1 bet, his chances of winning (W) and losing (L) are as follows:

P(W) = \frac{4}{38} \\P(L) = 1-P(W) = 1-\frac{4}{38} \\P(L) = \frac{34}{38}

The expected value of the bet is given by the probability of winning multiplied by the payout ($8), minus the probability of losing multiplied by the bet cost ($1)

EV=\frac{4}{38}*\$8 -\frac{34}{38}*\$1\\EV= -\$0.05

On each bet, the player is expected to lose 5 cents ($0.05).

4 0
3 years ago
What's the sum of 6(-2.1k - 2) + (7k + 5)
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The sum of 6(-2.1k-2) + (7k+5) is  -5.6k-7
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