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Sedbober [7]
3 years ago
5

Dillon read 1/5 of a book on Monday and 2/5 of the book on Tuesday. What fraction of the book did he read on Monday and Tuesday?

Mathematics
1 answer:
igor_vitrenko [27]3 years ago
3 0

Answer:

Fraction of Book Dillon Read on Monday and Tuesday is \mathbf{\frac{3}{5} }

Step-by-step explanation:

Dillon read book on Monday = \frac{1}{5}

Dillon read book on Tuesday = \frac{2}{5}

We need to find fraction of the book did he read on Monday and Tuesday

So, Fraction of Book Dillon Read on Monday and Tuesday= Book read on Monday + Book read on Tuesday

Fraction of Book Dillon Read on Monday and Tuesday= \frac{1}{5}+\frac{2}{5}

=\frac{1+2}{5} \ (Taking \ LCM \ of \ 5 \ and \ 5 \ we \ get \ 5) \\=\frac{3}{5}

So, Fraction of Book Dillon Read on Monday and Tuesday is \mathbf{\frac{3}{5} }

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4^10

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Alan bought 5 feet of fabric. How much is this in yards​
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Answer:

15 yards.

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Solve the equation. dy dx = ay + b cy + d , where a, b, c, and d are constants. (assume a ≠ 0 and ay + b ≠ 0.)
Reil [10]

 

It solves it in x. the solution for y includes heavy use of the product log function.

dy/dx                                = ay + b/cy +d

(cy +d/ ay + b) dy            = dx

∫ (cy +d/ ay + b) dy          = x (t) + C

 

Into solving the integral, integration by parts followed by u substitution and another integration by parts.

 

∫ (cy +d/ ay + b) dy

u            = cy + d dv          = dy/ay + b

du          = c dy v               = ln I ay + b l / a

 

Then, use u substitution for the new integral

 

u            = ay + b

du          = a dy

∫ ln l ay + b I dy                = ∫ ln IuI /a du    = 1/a ∫ ln luI du

 

Integrating the natural log includes thus far another integration by parts

r             = ln IuI ds            = du

dr          = du / u (s)           = du

∫ ln IuI / du                         = u ln IuI - ∫ du   = u ln IuI - ∫ a dy                                                                                   = (ay + b) ln Iay +bl – ay

 

The original integral of expression

∫ (cy +d/ ay + b) dy             = cy + d/a ln lay+bl – c/a² [(ay+b) ln lay+bl – ay]

Then simplify

∫ (cy +d/ ay + b) dy             = cy + d/a ln lay+bl – c/a²[(ay+b) ln lay+bl – ay]

                                           = a (cy + d)/a² ln lay+bl – c (ay+b)/ a²ln lay+bl +                                                               c/a² ay

                                           = cay + ad – cay – cb/ a² ln lay+bl + cay/a²

                                           = ad – cb/a²ln lay+bl + cy/a

 The final answer will be

x(t) + C                               = ad – cb/a² ln lay+bl + cy/a

x(t)                                     = ad – cb/a² ln lay+bl + cy/a + k

 

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3 0
3 years ago
X –12 = -8x + 6 a.x = 2 b.x = -2 c.x = 3 d.x = -3
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Answer:

<u>(a) x = 2</u>

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Next, solve for x by isolating it to one side of the equation. Here, we'll have to divide 18 by 9 (do the opposite of what 9 is doing with x; instead of multiplying it with 18 like it currently is with x, divide 18 by it.)

x = \frac{18}{9}

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Therefore, your answer is (a), since x = 2.

<em>I hope this helps! I would really appreciate it if you would please mark me brainliest! Have a blessed day!</em>

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