Answer:
a.) Between 0.5 and 3 seconds.
Step-by-step explanation:
So I just went ahead and graphed this quadratic on Desmos so you could have an idea of what this looks like. A negative quadratic, and we're trying to find when the graph's y-values are greater than 26.
If you look at the graph, you can easily see that the quadratic crosses y = 26 at x-values 0.5 and 3. And, you can see that the quadratic's graph is actually above y = 26 between these two values, 0.5 and 3.
Because we know that the quadratic's graph models the projectile's motion, we can conclude that the projectile will also be above 26 feet between 0.5 and 3 seconds.
So, the answer is a.) between 0.5 and 3 seconds.
22 I think If I worked it out right
-19.59 is your answer because u do PEMDAS and that would be 8.1*(-1.9) which gives you -15.39 Then you do -4.2+-15.39 and you would get -19.59
Answer:
Option D - x = 3 3/5
Step-by-step explanation:
Lets make the left side into an improper fraction :
2 2/5 = 12/5
Now let's make both fraction into equivalent ones but with the same denominator :
2/3 = 10/15
12/5 = 36/15
Now we substitute the equivalent values back into the equation :
10/15 × x = 36/15
Now we multiply both sides by 15 to remove the denominators:
10 × x = 36
Now we divide both sides by 10 and simplify :
x = 36/10
x = 18/5
x = 3 3/5
So our answer will be Option D
Hope this helped and brainliest please
