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Free_Kalibri [48]
3 years ago
13

I need help pls to do this​

Mathematics
1 answer:
VMariaS [17]3 years ago
8 0

Answer:

I don't plz like explain the question

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Please Help!
enot [183]
A
Because she deposits the same amount but got 60 dollars more for the birthday money.
5 0
3 years ago
What equation is graphed in this figure?
bixtya [17]
The answer is C

Here is the process, hope it helps!
y+2=-3/2(x-2)
y+2=-3/2x+3
y=-3/2x+1

4 0
3 years ago
A researcher claims that the mean of the salaries of elementary school teachers is greater than the mean of the salaries of seco
Brut [27]

Answer:

t=\frac{(48250-45630)}{\sqrt{\frac{3900^2}{26}+\frac{5530^2}{24}}}}=1.921  

df=n_{A}+n_{B}-2=26+24-2=48

Since is a one sided test the p value would be:

p_v =P(t_{(48)}>1.921)=0.0303

If we compare the p value and the significance level given \alpha=0.05 we see that p_v so we can conclude that we have enough evidence to reject the null hypothesis, and we can conclude that the mean for elementary school teachers is significantly higher than the mean for secondary teachers at 5% of significance

Step-by-step explanation:

Data given and notation

\bar X_{A}=48250 represent the mean of elementary teachers

\bar X_{B}=45630 represent the mean for secondary teachers

s_{A}=3900 represent the sample standard deviation for elementary teacher

s_{B}=5530 represent the sample standard deviation for secondary teachers

n_{A}=26 sample size selected

n_{B}=24 sample size selected  

\alpha=0.05 represent the significance level for the hypothesis test.

t would represent the statistic (variable of interest)

p_v represent the p value for the test (variable of interest)

State the null and alternative hypotheses.

We need to conduct a hypothesis in order to check if the mean of the salaries of elementary school teachers is greater than the mean of the salaries of secondary school teachers, the system of hypothesis would be:

Null hypothesis:\mu_{A}-\mu_{B}\leq 0

Alternative hypothesis:\mu_{A}-\mu_{B}>0

We don't know the population deviations, so for this case is better apply a t test to compare means, and the statistic is given by:

t=\frac{(\bar X_{A}-\bar X_{B})}{\sqrt{\frac{s^2_{A}}{n_{A}}+\frac{s^2_{B}}{n_{B}}}} (1)

t-test: "Is used to compare group means. Is one of the most common tests and is used to determine whether the means of two groups are equal to each other".

Calculate the statistic

We can replace in formula (1) the info given like this:

t=\frac{(48250-45630)}{\sqrt{\frac{3900^2}{26}+\frac{5530^2}{24}}}}=1.921  

P-value

The first step is calculate the degrees of freedom, on this case:

df=n_{A}+n_{B}-2=26+24-2=48

Since is a one sided test the p value would be:

p_v =P(t_{(48)}>1.921)=0.0303

Conclusion

If we compare the p value and the significance level given \alpha=0.05 we see that p_v so we can conclude that we have enough evidence to reject the null hypothesis, and we can conclude that the mean for elementary school teachers is significantly higher than the mean for secondary teachers at 5% of significance

5 0
2 years ago
1. A grocery store just received a shipment of 200 dozen eggs. If 12 eggs = 1 dozen, how many eggs did
melisa1 [442]

Answer:

2400 eggs

Step-by-step explanation:

12*200=2400

4 0
2 years ago
Read 2 more answers
a set of angels has a ratio of 5:2 . If the larger angle measures 105 degrees then what is the measure of the smaller angle
Igoryamba

Answer:

42

Step-by-step explanation:

6 0
3 years ago
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