3 years ago

Suppose y varies inversely with x, and y = 39 when x = 13. What is the value of y when x = 26 ?

Mathematics

1 answer:

Fittoniya [83]3 years ago

6 0

9514 1404 393

Answer:

y = 39/2 = 19.5

Step-by-step explanation:

When x is multiplied by 2 from 13 to 26, y will be multiplied by the inverse of that:

y = (1/2)(39) = 39/2 = 19.5

You might be interested in

Plz help me with this question thanks

Verizon [17]

Answer:

Step-by-step explanation:

7 0

3 years ago

G=x-c/x. for x<br><br>how do yoy make this an equation for x? help

zzz [600]

1.
$\displaystyle \text{if }\quad G=x- \frac{C}{x} \\\\$

$x \neq 0$

Multiply both sides by x:

$\displaystyle Gx=x\bigg(x- \frac{C}{x}\bigg )\\\\Gx=x^2-C$

Subtract from both sides Gx:
$Gx-Gx=x^2-C-Gx\\x^2-Gx-C=0$

Then solve this equation:

$\displaystyle x^2-Gx-C=0\\\\x_{1,2}= \frac{G\pm \sqrt{G^2+4C} }{2}$

2.
$\displaystyle\text{if}\quad G= \frac{x-C}{x}$

$x \neq 0$

Multiply both sides by x:

$Gx=x-C$

Subtract from both sides Gx:

$x-C-Gx=0$

Then solve this equation:

$\displaystyle x-Gx-C=0\\x(1-G)=C\\x= \frac{C}{1-G}$

7 0

3 years ago

What is the first step to solve the equation x^2-3=15

Otrada [13]

You will need to add 3 to each side.

x^2-3=15

+3 +3

x^2=12

and go from there

6 0

3 years ago

Read 2 more answers