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3 years ago

A figure has vertices at the points (6,5), (6,-4), (-4,-4) and (-4,5). What is the area of the figure

Mathematics

1 answer:

Oxana [17]3 years ago

7 0

Answer:

90 units²

Step-by-step explanation:

The rectangular figure is 10 units wide (from -4 to +6) and 9 units high (from -4 to +5), so its area is 10·9 = 90 square units.

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Paige had 18 dollars. She spent 6 of these dollars

Tpy6a [65]

Answer:

It would be 18-6 = 12

Step-by-step explanation:

6 0

3 years ago

Read 2 more answers

- Previous 11.1.3 Quiz: The Pythagorean Theorem A WXY is a right triangle. √36 √18 W √18 O A. True O B. False ← PREVIOUS sta De

meriva

Since (√36)² = (√18)²+(√18)², hence the triangle WXY is a right angle

<h3>What is Pythagoras theorem</h3>

The theorem states that the square of the hypotenuse is equal to the sum of the square of other two sides

For a triangle to be right angled, it must obey the law.

Given

Hypotenuse =√36

Other sides = √18 and √18

(√36)² = 36

(√18)²+(√18)²= 18 + 18

(√18)²+(√18)² = 36

Since (√36)² = (√18)²+(√18)², hence the triangle WXY is a right angle

Learn more on Pythagoras theorem here: brainly.com/question/343682

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2 years ago

An insurance company is interested in conducting a study to to estimate the population proportion of teenagers who obtain a driv

nlexa [21]

Answer:

n=1041 or higher

Step-by-step explanation:

Previous concepts

A confidence interval is "a range of values that’s likely to include a population value with a certain degree of confidence. It is often expressed a % whereby a population means lies between an upper and lower interval".

The margin of error is the range of values below and above the sample statistic in a confidence interval.

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

The population proportion have the following distribution

$p \sim N(p,\sqrt{\frac{\hat p(1-\hat p)}{n}})$

2) Solution to the problem

In order to find the critical value we need to take in count that we are finding the interval for a proportion, so on this case we need to use the z distribution. Since our interval is at 99% of confidence, our significance level would be given by $\alpha=1-0.99=0.01$ and $\alpha/2 =0.005$ . And the critical value would be given by:

$z_{\alpha/2}=-2.58, z_{1-\alpha/2}=2.58$

The margin of error for the proportion interval is given by this formula:

$ME=z_{\alpha/2}\sqrt{\frac{\hat p (1-\hat p)}{n}}$ (a)

And on this case we have that $ME =\pm 0.04$ and we are interested in order to find the value of n, if we solve n from equation (a) we got:

$n=\frac{\hat p (1-\hat p)}{(\frac{ME}{z})^2}$ (b)

Since we don't have a prior estimation for th proportion of interest, we can use this value as an estimation $\hat p =0.5$ And replacing into equation (b) the values from part a we got: