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vekshin1
3 years ago
12

A figure has vertices at the points (6,5), (6,-4), (-4,-4) and (-4,5). What is the area of the figure

Mathematics
1 answer:
Oxana [17]3 years ago
7 0

Answer:

  90 units²

Step-by-step explanation:

The rectangular figure is 10 units wide (from -4 to +6) and 9 units high (from -4 to +5), so its area is 10·9 = 90 square units.

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Zoey needs at least $30 to buy a gift. She has $12. Which inequality could Zoey use to find out how much more money (m) she need
melisa1 [442]

Answer:

The answer is C

Step-by-step explanation:

She only could use 30 ≤ 12 + m to solve for how much more money she needs. m > 18

4 0
3 years ago
I don't know how to do this please help ​
postnew [5]
The answer is 18.8
Just divide 94/5
6 0
3 years ago
The ratio between the areas of two similar polygons is 3i4. What is the ratio between the lengths of their corresponding sides
JulsSmile [24]

Answer:

11

Step-by-step explanation:

5 0
2 years ago
Elisa is nearing graduation. She just met with her counselor and he showed her this information.
Arada [10]

Answer: $14,000

Step-by-step explanation:

Given the following :

Room & Board = $11,500

Work - study = $8000

Grant & scholarship = $9500

Tuition fee = $9500

If she pays balance with a student loan, how much will she need to borrow:

Elisha's bill:

Tuition fee and room and board

($9500 + $11500) = $21,000

Elisha's earning:

Work - study and scholarship & grant

($8000 + $9500) = $17500

Therefore,

Amount to borrow per year :

$21,000 - $17,500 = $3500

For four years :

4 × $3,500 = $14,000

8 0
3 years ago
How many sequences of 0s and 1s of length 19 are there that begin with a 0, end with a 0, contain no two consecutive 0s, and con
sladkih [1.3K]

65 sequences.

Lets solve the problem,

The last term is 0.

To form the first 18 terms, we must combine the following two sequences:

0-1 and 0-1-1

Any combination of these two sequences will yield a valid case in which no two 0's and no three 1's are adjacent

So we will combine identical 2-term sequences with identical 3-term sequences to yield a total of 18 terms, we get:

2x + 3y = 18

Case 1: x=9 and y=0

Number of ways to arrange 9 identical 2-term sequences = 1

Case 2: x=6 and y=2

Number of ways to arrange 6 identical 2-term sequences and 2 identical 3-term sequences =8!6!2!=28=8!6!2!=28

Case 3: x=3 and y=4

Number of ways to arrange 3 identical 2-term sequences and 4 identical 3-term sequences =7!3!4!=35=7!3!4!=35

Case 4: x=0 and y=6

Number of ways to arrange 6 identical 3-term sequences = 1

Total ways = Case 1 + Case 2 + Case 3 + Case 4 = 1 + 28 + 35 + 1 = 65

Hence the number of sequences are 65.

Learn more about Sequences on:

brainly.com/question/12246947

#SPJ4

8 0
2 years ago
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