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3 years ago

Divya also wants to make fruit smoothies for dessert. She purchases

Mathematics

2 answers:

MAVERICK [17]3 years ago

6 0

Answer:

Divya purchases a container of rice milk at $3.49

two pounds of strawberries, $4.99 each; $9.98

six bananas at $0.75 each; $4.50

Therefore,

$3.49+$9.98+$4.50=$17.97

Jane spends a total of $17.97 on dessert.

Step-by-step explanation:

A cheerful teen willing to help,

stay salty,

be positive,

hope you find this useful...

Slav-nsk [51]3 years ago

5 0

Answer:

$17.97

Step-by-step explanation:

add everything up

- bananas: 6(0.75) = $4.50

- rice milk: $3.49

- strawberries: 2(4.99) = $9.98

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What is the answer in 8=2x+4

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Answer:

x = 2

Step-by-step explanation:

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3 years ago

The combined weight of 2 identical dice, 5 identical balls and 4 identical marbles was 260 grams. The combined weight of one die

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Answer:

The total weight of one die, one ball, and one marble is 75 grams.

Step-by-step explanation:

Consider the provided information.

Let d represents the number of dice, b represents the number of balls and m represents the number of marbles.

So according to the question.

The combined weight of 2 identical dice, 5 identical balls and 4 identical marbles was 260 grams.

$2d+5b+4m=260$ ....(1)

The combined weight of one die and one marble was 55 grams.

$d+m=55$

$m=55-d$ ....(2)

3 balls weighed the same as two dice.

$3b=2d$

Multiply both sides by 5 and divide by 3.

$5b=\frac{10}{3}d$ .....(3)

Now put the value of equation 2 and 3 in equation 1.

$2d+\frac{10}{3}d+4(55-d)=260$

$2d+\frac{10}{3}d+220-4d=260$

$\frac{6d+10d-12d}{3}=40$

$4d=120$

$d=30$

Put d=30 in equation 2.

$m=55-30$

$m=25$

Put d=30 in equation 3.

$5b=\frac{10}{3}\times 30$

$5b=100$

$b=20$

The total weight (in grams) of one die, one ball, and one marble is:

$d+m+b=25+20+30$

$d+m+b=75$

The total weight of one die, one ball, and one marble is 75 grams.

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3 years ago

Do not round intermediate calculations. round your answers to two decimal places. a. define a random variable number of times th

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Observations can you make from a comparison of the number of water supply stoppages reported by owner-occupied units versus renter-occupied units 1.

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x = no. of times owner-occupied units had a water supply stoppage.

<h3>What is the probability at x =0?</h3>

P(x=0) = 547000/14770000

P(x=0) = 0.0370

Similarly, we have at x=1

P(x=1) = 5012000/14770000

P(x=1) = 0.3393

P(x=2) = 6110000/14770000

P(x=2) = 0.4137

P(x=3) = 2544000/14770000

P(x=3) = 0.1722

P(x=4) = 557000/14770000

P(x=4) = 0.0378

x f(x)

0 0.0370

1 0.3393

2 0.4137

3 0.1722

4 0.0378

Total 1

Observations can you make from a comparison of the number of water supply stoppages reported by owner-occupied units versus renter-occupied units 1.

To learn more about the probability distribution visit:

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2 years ago

A bag contains purple marbles and white marbles, 68 in total. The number of purple marbles is 4 less than 5 times the number of

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Answer: 56 purple marbles.

Step-by-step explanation:

Let be "p" the number of purple marbles in the bag and "w" the number of white marbles in the bag.

You can set up the following System of equations:

$\left \{ {{p+w=68} \atop {p=5w-4}} \right.$