-(11+sqrt(121-4*18))/2 = -(11 +sqrt(49))/2 = -9
Or
-(11-sqrt(121-4*18))/2 = -(11-sqrt(49))/2 = -2
D is the answer
Answer:
y = -x - 2
Step-by-step explanation:
Find two points on the line
(0, -2)
(4, -6)
(Y2-Y1)/(X2-X1) = gradient of the line
Where (X1,Y1) = (0, -2) and (X2,Y2) = (4, -6)
(-6--2)/(4-0)
(-6+2)/4
(-4)/(4)
-1
Y = (-1)X + c
Substitute either set of coordinates in to find c.
(0, -2)
Y = (-1)X + c
-2 = (-1)0 + c
-2 = 0 + c
-2 = c
(4,-6)
Y = (-1)X + c
-6 = (-1)4 + c
-6 = -4 +c
-6 + 4 = c
-2 = c
Y = -X -2
25% 3/10 1/3 and 37.5%
.25,.30,.33,.375
Speed=distance/time
suppose the distance of the first day is d, and the time is t
distance of the second day: d+0.17d=1.17d
time of the second day: t+0.2t=1.2t
speed of the second day: 1.17d/1.2t=0.975(d/t)=(1-0.025)(d/t)
so the speed of the second day is 2.5% slower than the first day.
Answer: 8. 3^4+n^4, 9. 7^3+m^4, and 10. s+2t^3.
Step-by-step explanation:
