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Taya2010 [7]
3 years ago
11

How do you answer a question on Brainly if there's already at least one answer? It should be possible, since I've seen questions

with many answers before.
Computers and Technology
2 answers:
Ad libitum [116K]3 years ago
6 0

Answer:

you go under the question that you want to answer

Explanation:

I am not a profinal expert

sukhopar [10]3 years ago
4 0

Answer: The people below are correct!

Explanation: Could you try friending me again? I’m sorry, my phone is acting weird. Also, could you help me with my business questions I’m about to upload, giving brainliest!

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Alicia spends all day at work on the Internet and then all night on social networking sites looking at the many interesting thin
Stels [109]

Answer:

Better regulate time spent on internet

Explanation:

Because of the time Alicia is spending on the internet, seeing interesting things that her friends are doing, and perhaps her life has been boring, this tend to play with her psychology and she will begin to become depressed and start disliking her life. In this case, the main mediator is the internet, and the best way she can deal with depression at this level is to reduce or regulate the amount of time that she spends on the internet.

4 0
3 years ago
A conventional uniprocessor has __________ .
lys-0071 [83]

Answer:

The correct option to the following question is option (A).

Explanation:

SISD is used in the uni-processors systems which executes an individual instruction streams at a time by which we control an individual memory for the storage of data.

It is the flow or the sequence of an individual data or instructions which controlled on the systems.

Whereas SISD is different from the SMID and it is not used in the Uni-processor systems

3 0
4 years ago
Which of the statements below are true about Digital Signatures?
Leokris [45]

Answer:

The answer is "Option a, and c".

Explanation:

Following are the description of the Digital Signature choices:

  • To change the physical transportation of paper or link files in the computerized messaging system, some processes should be identified and utilized in digital signatures, which enables documentation to be validated unforgivably.
  • Using public-key cryptography, digital signatures, that's an exquisite system, that's why options a and b are correct.
  • Digital signatures are not a central authority, that's why the option B is wrong.
5 0
3 years ago
Write a static method called bothStart that allows the user to input two Strings and returns the String that is the longest subs
marishachu [46]

Answer:

  1.    public static String bothStart(String text1, String text2){
  2.        String s = "";
  3.        if(text1.length() > text2.length()) {
  4.            for (int i = 0; i < text2.length(); i++) {
  5.                if (text1.charAt(i) == text2.charAt(i)) {
  6.                    s += text1.charAt(i);
  7.                }else{
  8.                    break;
  9.                }
  10.            }
  11.            return s;
  12.        }else{
  13.            for (int i = 0; i < text1.length(); i++) {
  14.                if (text1.charAt(i) == text2.charAt(i)) {
  15.                    s += text1.charAt(i);
  16.                }else{
  17.                    break;
  18.                }
  19.            }
  20.            return s;
  21.        }
  22.    }

Explanation:

Let's start with creating a static method <em>bothStart()</em> with two String type parameters, <em>text1 </em>&<em> text2</em> (Line 1).  

<em />

Create a String type variable, <em>s,</em> which will hold the value of the longest substring that both inputs start with the same character (Line 2).

There are two possible situation here: either <em>text1 </em>longer than<em> text2 </em>or vice versa. Hence, we need to create if-else statements to handle these two position conditions (Line 4 & Line 13).

If the length of<em> text1</em> is longer than <em>text2</em>, the for-loop should only traverse both of strings up to the length of the <em>text2 </em>(Line 5). Within the for-loop, we can use<em> charAt()</em> method to extract individual character from the<em> text1</em> & <em>text2 </em>and compare with each other (Line 15). If they are matched, the character should be joined with the string s (Line 16). If not, break the loop.

The program logic from (Line 14 - 20) is similar to the code segment above (Line 4 -12) except for-loop traverse up to the length of <em>text1 .</em>

<em />

At the end, return the s as output (Line 21).

5 0
3 years ago
Help101111 avatar can we be friend's please? My name is Keegan. what is yours?
kherson [118]

Answer:

foot

Explanation:

Sub to Ssundee

6 0
3 years ago
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