Answer:
The answer to your question is: letter D
Step-by-step explanation:
The interval graph is (5, 9] , open five, nine close. As an inequality this interval is:
5 < x ≤ 9
a) Letter A is incorrect because it suggests that two sections in the graph must be shaded and in this graph there is only one section shaded.
b) Letter B is incorrect because in the graph we observe that before 5 there must be a parenthesis because the point is open and the point in 9 is shaded so it must be follow by a ].
c) Letter c is alos incorrect because it suggests two sections shaded in the graph and it shows only one.
Answer:
(a) 110 mm Hg
(b) 70 mm Hg
(c) 3/4 second
(d) see the attachment
Step-by-step explanation:
(a) The sine function has a maximum value of +1, so the maximum value of p is ...
pmax = 20·(+1) +90 = 20+90 = 110 . . . . . mm Hg
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(b) The sine function has a minimum value of -1, so the minimum value of p is ...
pmin = 20·(-1) +90 = -20+90 = 70 . . . . . mm Hg
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(c) The period of the sine function is 2π, so the value of t that makes the argument be 2π will be the period.
8π/3·t = 2π
t = 2π·3/(8π) = 3/4 . . . . . . multiply by the inverse of the coefficient of t
The period of her heartbeat cycle is 3/4 seconds.
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(d) a graph is attached.
4× 4 3/10= 4×43/10= 86/5= 17 1/5
X/5=x-5
x = 5x-25
4x = 25
x=25/4