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andrew-mc [135]
3 years ago
9

Brad owns 3 surfboards and 2 wet suits. If he takes one surfboard and one wet suit to the beach, how many different combinations

can he choose? *
Mathematics
1 answer:
Reptile [31]3 years ago
6 0

Answer:

1

Step-by-step explanation:

He only has 1 wetsuit and 1 surfboard.

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A pair of bottlenose dolphins at an aquarium are fed 45 pounds of fish each day. The aquarium recently added another dolphin. Ho
Arte-miy333 [17]

Answer:

67.5 pound of fish are needed to feed 3 dolphins

good luck buddy

8 0
3 years ago
Consider the following game, played with three standard six-sided dice. If the player ends with all three dice showing the same
ddd [48]

Answer:

a

 P(A) =  \frac{1}{36}

b

P(B) = \frac{15}{36}

c

P(U) = \frac{11}{36}

Step-by-step explanation:

From the question we are told that

   The  number of dice is  n  =  3

Generally  for all three dice to show the same number the second and the third dice must have the same outcome  as the outcome of the first dice.

This means that the number of outcome the first die can  have is  6  (6 sides), the number of outcome which the second and the third dice can have is  1 (they must match the first )

So the probability that all three dice show the same number on the first roll is mathematically represented as

      P(A) =  \frac{6}{6} * \frac{1}{6} *  \frac{1}{6}

=>   P(A) =  \frac{1}{36}

Generally for two of the three dice show the same number after the first roll then the number of outcome for  one of the  dice would be is  6 , the number of outcome for another one must be   1(i.e it must match the first ) , the number of outcome for the remaining one must be   5 (i.e it can show any of the remaining  5  sides which the first and second dice are not showing )

Now the number of ways of selecting this 2 dice that show the same number from the 3 dice is mathematically represented as

     N  =  ^3C_2

Here C stands for combination

So

      N  =  ^3C_2  = 6

So the probability that exactly two of the three dice show the same number after the first roll is mathematically represented as  

      P(B) = N   \frac{1}{6} *  \frac{5}{6}

=>  P(B) = \frac{15}{36}

Generally from the question we are told that if two dice match, the player re-rolls the die that does not match.

Now the probability that  the die that did not match the first  time will match the second time is

     P(E ) =  \frac{1}{6}

Generally if that one die does not show the same number in the second round , the probability that it will match  in the third round is

    P(R) =  \frac{5}{6} *  \frac{1}{6}

Generally the probability that he wins (i.e when all three are showing the same number ) and  exactly two is showing the same number is mathematically represented as

       P(K) =  P(E)* P(B) + P(R)* P(B)

=>    P(K) =  \frac{1}{6} * \frac{15}{36}  +  \frac{5}{6} *  \frac{1}{6} * \frac{15}{36}

=>  P(K)= \frac{165}{1296}

So the probability that the player wins, conditioned on exactly two of the three dice showing the same number after the first roll is mathematically represented as  

    P(U) =  \frac{\frac{165}{1296}}{\frac{15}{36} }

=>  P(U) = \frac{11}{36}

     

 

6 0
3 years ago
A store is having a 20% off sale. If the
Aleks [24]

Answer:

$64.32

Step-by-step explanation:

What you do is:

$53.60×20% → $53.60×0.2

$53.60×0.2=$10.72

$10.72 is the amount of money taken off because of the sale.

Then what you do is:

$53.60+$10.72=_____

53.60

<u>+10.72</u>

64.32

The original price was $64.32.

Hope this helps! Please mark my answer brainliest!

3 0
3 years ago
Read 2 more answers
elaina wrote two correct variable expressions to represent the phrase “one-fourth of a number.” which variable expressions could
antiseptic1488 [7]
One-fourth of a number

1/4n and n/4
5 0
3 years ago
Read 2 more answers
The Hu family goes out for lunch, and the price of the meal is $52. The sales tax on the meal is 6%, and the
Olegator [25]

Answer:

62.92

Step-by-step explanation:

21 percent of 52$ is 10.92 then add em together hope it helps

7 0
2 years ago
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