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3 years ago

Which is the greatest among root 2, 3 root 4 and 4 root 3?

Mathematics

1 answer:

Sveta_85 [38]3 years ago

6 0

Answer:

4^1/3 is greatest among the given

Step-by-step explanation:

√2 , 4^1/3 , 3^1/4

Find the LCM of 2, 3 , 4= 12

i ) √2 =2^1/2 = 2^6/12=(2^6)^1/12

= (64)^1/12

ii ) 4^1/3 = 4^4/12 = (4^4)^1/12

= (256)1/12

iii )3^1/4 = 3^3/12 = ( 3³ )^1/12

= (27)^1/12

Therefore ,

(256)^1/12 > (64)^1/12 > (27)^1/12

4^1/3 > 2^1/2 > 3^1/4

4^1/3 is greatest among the given

number

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8 19. Marcus claims that fractions with denominators 1 through 10 follow a pattern

navik [9.2K]

Answer:

Step-by-step explanation:

Marcus is not correct because 1/12 converts to the repeating decimal 0.8333... but 3/12 converts to 0.25 which is not a repeating decimal.

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2 years ago

A photography studio charges a sitting fee of $45 plus $2.50 per photograph. Another photography studio has no sitting fee but c

Sveta_85 [38]

The answer would be 12

5 1

3 years ago

Read 2 more answers

Given the functions f(x) = 2x -1 and g(x) =

Novosadov [1.4K]

Answer:

Please check the explanation.

Step-by-step explanation:

Given

f(x) = 2x - 1

g(x) = 2 - x

f(x) + g(x) = (2x - 1) + (2 - x)

= 2x -1 + 2 - x

= x + 1

f(x) - g(x) = (2x - 1) - (2 - x)

= 2x - 1 - 2 + x

= 3x - 3

g(-5) - f(-5)

Putting x = -5 in g(x) = 2 - x

g(x) = 2 - x

g(-5) = 2 - (-5) = 2+5 = 7

Putting x = -5 in f(x) = 2x - 1

f(x) = 2x - 1

f(-5) = 2(-5) - 1

= -10 - 1

= -11

Thus,

g(-5) - f(-5) = 7 - (-11) = 7+11 = 18

f(x).g(x) = (2x - 1) (2 - x) = -2x² + 5x - 2

f(g(x)) = f(2-x)

= 2(2-x)-1

= 4-2x-1

= 3-2x

6 0

3 years ago

Coco's garden has 888 tomato plants, 444 pepper plants, 333 squash plants, and 666 pumpkin plants.

AveGali [126]

888 + 444 + 333 + 666 = 2331 / 7 = 3

3 * 222 = 666

There are 666 of the plants

I hope this helps :)

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3 years ago

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Big chickens: The weights of broilers (commercially raised chickens) are approximately normally distributed with mean 1387 grams

Nataliya [291]

Answer:

a) 0.2318

b) 0.2609

c) No it is not unusual for a broiler to weigh more than 1610 grams

Step-by-step explanation:

We solve using z score formula

z-score is is z = (x-μ)/σ, where x is the raw score, μ is the population mean, and σ is the population standard deviation.

Mean 1387 grams and standard deviation 192 grams. Use the TI-84 Plus calculator to answer the following.

(a) What proportion of broilers weigh between 1150 and 1308 grams?

For 1150 grams

z = 1150 - 1387/192

= -1.23438

Probability value from Z-Table:

P(x = 1150) = 0.10853

For 1308 grams

z = 1308 - 1387/192

= -0.41146

Probability value from Z-Table:

P(x = 1308) = 0.34037

Proportion of broilers weigh between 1150 and 1308 grams is:

P(x = 1308) - P(x = 1150)

0.34037 - 0.10853

= 0.23184

≈ 0.2318

(b) What is the probability that a randomly selected broiler weighs more than 1510 grams?

1510 - 1387/192

= 0.64063

Probabilty value from Z-Table:

P(x<1510) = 0.73912

P(x>1510) = 1 - P(x<1510) = 0.26088

≈ 0.2609

1610- 1387/192

= 1.16146

Probability value from Z-Table:

P(x<1610) = 0.87727

P(x>1610) = 1 - P(x<1610) = 0.12273

≈ 0.1227

No it is not unusual for a broiler to weigh more than 1610 grams

8 0

3 years ago