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2 years ago

Which is the greatest among root 2, 3 root 4 and 4 root 3?

Mathematics

1 answer:

Sveta_85 [38]2 years ago

6 0

Answer:

4^1/3 is greatest among the given

Step-by-step explanation:

√2 , 4^1/3 , 3^1/4

Find the LCM of 2, 3 , 4= 12

i ) √2 =2^1/2 = 2^6/12=(2^6)^1/12

= (64)^1/12

ii ) 4^1/3 = 4^4/12 = (4^4)^1/12

= (256)1/12

iii )3^1/4 = 3^3/12 = ( 3³ )^1/12

= (27)^1/12

Therefore ,

(256)^1/12 > (64)^1/12 > (27)^1/12

4^1/3 > 2^1/2 > 3^1/4

4^1/3 is greatest among the given

number

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Answer:

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prove that hg(x)=19

Step-by-step explanation:

step 1: hog(x)=h[g(x)]

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step 4: (8x-5)(8x-5)+6

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2 years ago

A bag contains 6 red apples and 5 yellow apples. 3 apples are selected at random. Find the probability of selecting 1 red apple

tester [92]

Answer: The required probability of selecting 1 red apple and 2 yellow apples is 36.36%.

Step-by-step explanation: We are given that a bag contains 6 red apples and 5 yellow apples out of which 3 apples are selected at random.

We are to find the probability of selecting 1 red apple and 2 yellow apples.

Let S denote the sample space for selecting 3 apples from the bag and let A denote the event of selecting 1 red apple and 2 yellow apples.

Then, we have

$n(S)=^{6+5}C_3=^{11}C_3=\dfrac{11!}{3!(11-3)!}=\dfrac{11\times10\times9\times8!}{3\times2\times1\times8!}=165,\\\\\\n(A)\\\\\\=^6C_1\times^5C_2\\\\\\=\dfrac{6!}{1!(6-1)!}\times\dfrac{5!}{2!(5-2)!}\\\\\\=\dfrac{6\times5!}{1\times5!}\times\dfrac{5\times4\times3!}{2\times1\times3!}\\\\\\=6\times5\times2\\\\=60.$

Therefore, the probability of event A is given by

$P(A)=\dfrac{n(A)}{n(S)}=\dfrac{60}{165}=\dfrac{4}{11}\times100\%=36.36\%.$

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2 years ago

The three lines given below form a triangle. Find the coordinates of the vertices of the triangle.

LenKa [72]

Answer:

(3, 5), (1, 2) and (5, 1)

Step-by-step explanation:

Make three systems with pairs of lines and solve them to work out the vertices.

1) Line 1 and line 2

-3x + 2y = 1
2x + y = 11

Double the second equation and subtract equations:

-3x + 2y - 2(2x + y) = 1 - 2(11)
-3x - 4x = 1 - 22
-7x = - 21
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Find y:

2*3 + y = 11
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The point is (3, 5)

2) Line 1 and line 3

-3x + 2y = 1
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Triple the second equation and add up equations:

-3x + 2y + 3(x + 4y) = 1 + 3(9)
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Find x:

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3) Line 2 and line 3

2x + y = 11
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Double the second equation and subtract the equations:

2x + y - 2(x + 4y) = 11 - 2(9)
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Find x:

x + 4*1 = 9
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Goshia [24]

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