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aleksandrvk [35]
2 years ago
8

Say yes if you hate edge2021?

Computers and Technology
2 answers:
insens350 [35]2 years ago
5 0

Answer:

Yes I hate it

Explanation:

Yes it's simple

iVinArrow [24]2 years ago
4 0

Answer:

yes and no 50/50

Explanation:

English - Hey, so I'm starting a little business. I'm going to be customizing shoes. If you want a pair of shoes please tell me. I will be putting another post with photos of shoes I've customized.

Spanish - Oye, estoy comenzando un pequeño negocio. Voy a personalizar zapatos. Si quieres un par de zapatos, dímelo. Estaré poniendo otra publicación con fotos de zapatos que he personalizado.

Insta account and website in progess

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Consider the following general code for allowing access to a resource:
Margaret [11]

Answer:

a) The code allows access even when  IsAccessAllowed(...) method fails.

b) Either use If

(dwRet = ACCESS_ALLOWED)

or use

if (dwRet == NO_ERROR)

to avoid flaw

Explanation:

Lets first see what the code chunk does:

DWORD dwRet = IsAccessAllowed(...);

if (dwRet == ERROR_ACCESS_DENIED) {

// Security check failed.

// Inform user that access is denied.

} else {

// Security check OK.

}

In the given code, DWORD is basically a data type for double word type integers and this is defined in windows.h

So there is DWORD type variable dwRet that is assigned a method calls.

The method is IsAccessAllowed() which checks if the access is allowed to user.

if (dwRet == ERROR_ACCESS_DENIED) condition basically checks if the value of DWORD type variable dwRet is equal to ERROR_ACCESS_DENIED

If this condition evaluates to true then the security checks fails and user is informed via some message or action that the access is denied.  But when the if condition evaluates to false then the else part executes which allows access.

So basically this chunk of code checks if the error ERROR_ACCESS_DENIED is returned.

Now the flaw in this program is what if the method IsAccessAllowed() by any reason. The reasons can be system failure or the memory failure. In memory failure case for example, the system returns out of memory error. So this means that the error is not  ERROR_ACCESS_DENIED. Instead it is out of memory error. So in such a case the user is allowed access as the if condition evaluates to false and else part executes. So if any other error is produced due to some reason like mentioned above, then user has unrestricted access.

This shows that the doe should not check for the failure or rely on checking ERROR_ACCESS_DENIED to allow access but instead it should check for success. Code should only give access privilege if access is allowed successfully or no error is produced.

So to avoid this flaw the code is altered as:

DWORD dwRet = IsAccessAllowed(...);

If (dwRet = ACCESS_ALLOWED) {

//Security check OK.

} else {

//Security check failed.

//Inform user that access is denied.

}

This will only allow access if ACCESS_ALLOWED evaluates to true and success is checked instead of failure here

You can also alter the if condition as:

If (dwRet = No_Error)

or

If (dwRet = 0)

The above if conditions checks if the access is allowed or if no error is produced. Only then it will allowed access otherwise not. So the access check is a success is checked first and failure (for any reason). The user is allowed access only if there is no error otherwise user is not allowed access.

6 0
3 years ago
Create an application named Percentages whose main() method holds two double variables. Assign values to the variables. Pass bot
lbvjy [14]

Answer:

The codes below implement the problem statements

Explanation:

public class Percentages {

public static void computePercent (int a,int b)

{

System.out.println(a+" is "+(a*100/b)+"% of "+b);    

}

 

public static void main(String []args)

{

int a=2;

int b=5;

computePercent(a,b);

computePercent(b,a);

}

}

<u> </u>

<u>Part(b) </u>

import java.util.*;

public class Percentages {

public static void computePercent (int a,int b)

{

System.out.println(a+" is "+(a*100/b)+"% of "+b);

}

 

public static void main(String []args)

{

Scanner s= new Scanner(System.in);

int a=s.nextInt();

int b=s.nextInt();

computePercent(a,b);

computePercent(b,a);

}

}

8 0
3 years ago
What is one of the main problems with shared web hosting? Select one: Sites that share resources are less susceptible to hacking
Pani-rosa [81]

Answer:

If one or more of the shared sites go down, then there is a good chance that your site will go down as well.

Explanation:

Shared web hosting is a form of web hosting service whereby more than one websites are placed on a single web server that connects to the internet.

Though it is cheaper, it has various problems. And over time, it has been concluded that the major problem associated with shared web hosting is the security issue.

This implies that "If one or more of the shared sites go down, then there is a good chance that your site will go down as well."

Some other problems associated with Shared web hosting are poor value, less flexibility, none advanced features, slow service, less support.

4 0
3 years ago
When you pass an array as an argument to a function, the function can modify the contents of the array?
taurus [48]
In most languages. Primitive data types ( char, int, float, bool, maybe string ) are usually passed by value, but compound data types are passed by reference, so you're not working on a copy but on the original.
8 0
2 years ago
4 brainly
Allushta [10]
Web designers like create websites for businesses
6 0
2 years ago
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