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2 years ago

Solve for n: 1/4 (n-2)=1/4n-1/2

Mathematics

1 answer:

alisha [4.7K]2 years ago

7 0

Answer:

See below:

Step-by-step explanation:

So, we start off with the equation: $\frac{1}{4} (n-2) = \frac{1}{4}n-\frac{1}{2}$

If we simplify, we can use the distrubutive property to simplify the equation:

Here is how it goes:

$\frac{1}{4} (n-2) = (\frac{1}{4} * n )+(\frac{1}{4}*-2)$

So upon simplification of that, we get here: $\frac{1}{4}n + -\frac{1}{2}= \frac{1}{4}n-\frac{1}{2}$

Hm, somethings off, do you see that they are the same thing...

So, that means that there would be infinately many solutions.

You can plugin any number and you would get the same result!

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4 years ago

a researcher at a major clinic wishes to estimate the proportion of the adult population of the united states that has sleep dep

Anna11 [10]

Answer:

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Step-by-step explanation:

We can solve the the problem by using the formula for minimum sample needed for interval estimate of a population proportion which is given by the formula

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As, p is not defined so we use the standard p and q which is 0.5 and 0.5.

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4 years ago

For the accompanying data set, draw a scatter diagram of the data.x 2 6 6 7 9y 3 2 6 9 5B. by hand compute the correlation coeff

zhenek [66]

Answer:

Step-by-step explanation:

Hello!

Given the data corresponding the variables:

x 2 6 6 7 9

y 3 2 6 9 5

The Scatterplot is attached.

To compute the correlation coefficient you need several auxiliary calculations:

∑X= 30

∑X²= 206

∑Y= 25

∑Y²= 155

∑XY= 162

$r= \frac{sumXY-\frac{(sumX)(sumY)}{n} }{\sqrt{[sumX^2-\frac{(sumX)^2}{n} ][sumY^2-\frac{(sumY)^2}{n} ]} }$

$r= \frac{162-\frac{(30)*(25)}{5} }{\sqrt{[206-\frac{(30)^2}{5} ][155-\frac{(25)^2}{5} ]} }$

r= 0.429 ≅ 0.43

The critical value for r has n-2 degrees of freedom, let's say for example you have α:0.05

$r_{n-2;\alpha } = r_{3;0.05 } = 0.878$

For a two-tailed test.

Because the correlation coefficient is positive and the absolute value of the correlation coefficient, _0.43___, is not greater than the critical value for this data set,_0.878__, no linear relationship exists between x and y.

I hope it helps!

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3 years ago