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mina [271]
3 years ago
10

Find the volume of the cone. Either enter an exact answer in terms of \piπpi or use 3.143.143, point, 14 for \piπpi and round yo

ur final answer to the nearest hundredth.

Mathematics
1 answer:
NeTakaya3 years ago
8 0

Answer:

Volume of the cone = 130.83 cubic units

Step-by-step explanation:

The question us incomplete without the diagram of the cone and it's dimensions as this would enable us get the exact answer.

Find attached the diagram used in solving the solution.

Volume of cone = ⅓ πr²h

Radius = r = 5 unit

Height = h = 5 unit

π = 3.14

By inserting the values of each variables, we have:

Volume of cone = ⅓ × 3.14× (5)² × 5

= ⅓ × 3.14× 25×5 = ⅓ × 3.14×125

Volume of cone = (392.5)/3

Volume of cone = 130.8333

Volume of cone = 130.83 cubic units (to the nearest hundredth)

Volume of cone = 130.83 unit³

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igor_vitrenko [27]

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3 years ago
Solve the inequality. |2x + 10| > 26
neonofarm [45]

Answer:

x > 8

x < -16

Step-by-step explanation:

2x + 10 > 26

2x + 10 - 10 > 26 - 10

2x > 16

2x/2 > 16/2

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The fan cost index represents the cost of four average price tickets
777dan777 [17]

9514 1404 393

Answer:

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  • hockey: $57.78

Step-by-step explanation:

Let s represent the FCI for soccer. The given values tell us ...

  s + (s +7.47) = 108.09

  2s = 100.62 . . . . . . . . . . subtract 7.47

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The FCI for soccer was $50.31; the FCI for hockey was $57.78.

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2 years ago
Two standardized​ tests, a and​ b, use very different scales of scores. the formula upper a equals 40 times upper b plus 50a=40×
Leona [35]
Adding (or subtracting) a constant to every data value adds (or subtracts) the same constant to measures of position such as center,percentiles, max or min.

Its shape and spread such as range, IQR, standard deviation remain unchanged.
When we multiply (or divide) all the data values by any constant, all measures of position (such as the mean, median, and percentiles) and measures of spread (such as the range, the IQR, and the standard deviation) are multiplied (or divided) by that same constant.
Part A:

The lowest score is a measure of location, so both addition and multiplying the lowest score of test B by 40 and adding 50 to the result will affect the lowest score of test A.

Thus, the lowest score of test A is given by 40(21) + 50 = 890

Therefore, the lowest score of test A is 890.



Part B:

The mean score is a measure of location, so both addition and multiplying the mean score of test B by 40 and adding 50 to the result will affect the lowest score of test A.

Thus, the mean score of test A is given by 40(29) + 50 = 1,210

Therefore, the mean score of test A is 890.



Part C:

The standard deviation is a measure of spread, so multiplying the standard deviation of test B by 40 will affect the standard deviation but adding 50 to the result will not affect the standard deviation of test A.

Thus, the standard deviation of test A is given by 40(2) = 80

Therefore, the standard deviation of test A is 80.



Part D

The Q3 score is a measure of location, so both addition and multiplying the Q3 score of test B by 40 and adding 50 to the result will affect the Q3 score of test A.

Thus, the Q3 score of test A is given by 40(28) + 50 = 1,170

Therefore, the Q3 score of test a is 1,170.



Part E:

The median score is a measure of location, so both addition and multiplying the median score of test B by 40 and adding 50 to the result will affect the median score of test A.

Thus, the median score of test A is given by 40(26) + 50 = 1,090

Therefore, the median score of test A is 1,090.



Part F:

The IQR is a measure of spread, so multiplying the IQR of test B by 40 will affect the IQR but adding 50 to the result will not affect the IQR of test A.

Thus, the IQR of test A is given by 40(6) = 240

Therefore, the IQR of test A is 240.
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Answer:

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