Choose a rational function with a removable discontinuity. A f(x)=x+1x+2f\left(x\right)=\frac{x+1}{x+2}f(x)= x+2 x+1 B g(x)=xx

Question

2 years ago

8

Choose a rational function with a removable discontinuity. A f(x)=x+1x+2f\left(x\right)=\frac{x+1}{x+2}f(x)= x+2 x+1 B g(x)=xx

2g\left(x\right)=\frac{x}{x^2}g(x)= x 2 x C h(x)=2x2−2x+1h\left(x\right)=\frac{2}{x^2-2x+1}h(x)= x 2 −2x+1 2 D j(x)=2xx2−1j\left(x\right)=\frac{2x}{x^2-1}j(x)= x 2 −1 2x

Mathematics

1 answer:

Dvinal [7] · Answer 1 · 2022-11-18T17:24:58+03:00

Dvinal [7]2 years ago

8 0

Answer:

ok i forgot answer but i think its 1 + 1 = 49e+02848923589 ye

Step-by-step explanation:

Choose a rational function with a removable discontinuity. A f(x)=x+1x+2f\left(x\right)=\frac{x+1}{x+2}f(x)= x+2 x+1 ​ B g(x)=xx

Choose a rational function with a removable discontinuity. A f(x)=x+1x+2f\left(x\right)=\frac{x+1}{x+2}f(x)= x+2 x+1 B g(x)=xx