What is the perimeter of this rectangle?

Which two ratios are equivalent to 10 : 12? 11:13 and 20:24 B. 10:12 and 11:13 C. 5:6 and 20:24

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Answer: 5;6

Step-by-step explanation:

10 divided by 2 is 5

12 divided by 2 is 6 and plus I got this answer correct

6 0

3 years ago

The lower the average monthly temperature, the higher the monthly heating bill.

sergejj [24]

The first option is correct

7 0

2 years ago

Anna, Beth and Colleen are softball players. This season, Anne had 65 base hits in 160 at-bats. Beth batting average was 0.399,

zheka24 [161]

Answer:

Anne is the best hitter as she has the best hitting average of 0.406

Step-by-step explanation:

Anne hits 65 bases out of 160 at - bats.

Beth's betting average = 0.399

Collin's hit = 40%

Now, we need to convert all the three hitting rates into same parameters to compare them with each other.

Average hit rate of Anne = $\frac{\textrm{Total numberof base}}{\textrm{Total number of at - bats}}$

$= \frac{65}{160} = 0.406$

⇒The betting average of Anne = 0.406

Now, The hit - rate of Collin = 40%

Converting the percentage rate into decimal, we get the hit rate of Collin

= $\frac{40}{100} = 0.40$

Hence, we get that Hitting Average of :

<u>Anne = 0.406</u>, Beth = 0.3999 and Collin = 0.400

Hence, from the above data Anne is the best hitter as she has the best hitting average of 0.406.

6 0

3 years ago

Read 2 more answers

Please help with any of this Im stuck and having trouble with pre calc is it basic triogmetric identities using quotient and rec

german

How I was taught all of these problems is in terms of r, x, and y. Where sin = y/r, cos = x/r, tan = y/x, csc = r/y, sec = r/x, cot = x/y. That is how I will designate all of the specific pieces in each problem.

#3

Let's start with sin here. $\frac{2\sqrt{5}}{5} = \frac{2}{\sqrt{5}}$ Therefore, because sin is y/r, r = $\sqrt{5}$ and y = +2. Moving over to cot, which is x/y, x = -1, and y = 2. We know y has to be positive because it is positive in our given value of sin. Now, to find cos, we have to do x/r.

cos = $\frac{-1}{\sqrt{5}} = \frac{-\sqrt{5}}{5}$

#4

Let's start with secant here. Secant is r/x, where r (the length value/hypotenuse) cannot be negative. So, r = 9 and x = -7. Moving over to tan, x must still equal -7, and y = $4\sqrt{2}$ . Now, to find csc, we have to do r/y.

csc = $\frac{9}{4\sqrt{2}} = \frac{9\sqrt{2}}{8}$

The pythagorean identities are

sin^2 + cos^2 = 1,

1 + cot^2 = csc^2,

tan^2 + 1 = sec^2.

#5

Let's take a look at the information given here. We know that cos = -3/4, and sin (the y value), must be greater than 0. To find sin, we can use the first pythagorean identity.

sin^2 + (-3/4)^2 = 1

sin^2 + 9/16 = 1

sin^2 = 7/16

sin = $\sqrt{7/16}$ = $\frac{\sqrt{7}}{4}$

Now to find tan using a pythagorean identity, we'll first need to find sec. sec is the inverse/reciprocal of cos, so therefore sec = -4/3. Now, we can use the third trigonometric identity to find tan, just as we did for sin. And, since we know that our y value is positive, and our x value is negative, tan will be negative.

tan^2 + 1 = (-4/3)^2

tan^2 + 1 = 16/9

tan^2 = 7/9

tan = - $\sqrt{7/9} = \frac{-\sqrt{7}}{3}$

#6

Let's take a look at the information given here. If we know that csc is negative, then our y value must also be negative (r will never be negative). So, if cot must be positive, then our x value must also be negative (a negative divided by a negative makes a positive). Let's use the second pythagorean identity to solve for cot.

1 + cot^2 = $(\frac{-\sqrt{6}}{2})^{2}$

1 + cot^2 = 6/4

cot^2 = 2/4

cot = $\frac{\sqrt{2}}{2}$

tan = $\sqrt{2}$

Next, we can use the third trigonometric identity to solve for sec. Remember that we can get tan from cot, and cos from sec. And, from what we determined in the beginning, sec/cos will be negative.

$(\frac{2}{\sqrt{2}})^2$ + 1 = sec^2