What is the perimeter of this rectangle?

7 points!!!! hep help help 2. When you are converting a decimal to a fraction, how do you know what to use as the denominator?

vitfil [10]

Step-by-step explanation:

Check to see if there is a number before (to the left of) the decimal. If there is, this number is the whole number of the fraction. So, 3 is the whole number. Place the number that falls after (to the right of) the decimal in the numerator; then use the decimal placement to determine the denominator.

3 0

3 years ago

Langston Hughes earns an annual salary of $76,700.00 as Chiet Pinancial Olhicer of

Sphinxa [80]

I think the answer 100,000

8 0

3 years ago

Suppose twenty-two communities have an average of = 123.6 reported cases of larceny per year. assume that σ is known to be 36.8

Delvig [45]

We are given the following data:

Average = m = 123.6
Population standard deviation = σ= psd = 36.8
Sample Size = n = 22

We are to find the confidence intervals for 90%, 95% and 98% confidence level.

Since the population standard deviation is known, and sample size is not too small, we can use standard normal distribution to find the confidence intervals.

Part 1) 90% Confidence Interval
z value for 90% confidence interval = 1.645

Lower end of confidence interval = $m-z *\frac{psd}{ \sqrt{n} }$
Using the values, we get:
Lower end of confidence interval= $123.6-1.645* \frac{36.8}{ \sqrt{22}}=110.69$

Upper end of confidence interval = $m+z *\frac{psd}{ \sqrt{n} }$
Using the values, we get:
Upper end of confidence interval= $123.6+1.645* \frac{36.8}{ \sqrt{22}}=136.51$

Thus the 90% confidence interval will be (110.69, 136.51)

Part 2) 95% Confidence Interval
z value for 95% confidence interval = 1.96

Lower end of confidence interval = $m-z *\frac{psd}{ \sqrt{n} }$
Using the values, we get:
Lower end of confidence interval= $123.6-1.96* \frac{36.8}{ \sqrt{22}}=108.22$

Upper end of confidence interval = $m+z *\frac{psd}{ \sqrt{n} }$
Using the values, we get:
Upper end of confidence interval= $123.6+1.96* \frac{36.8}{ \sqrt{22}}=138.98$

Thus the 95% confidence interval will be (108.22, 138.98)

Part 3) 98% Confidence Interval
z value for 98% confidence interval = 2.327

Lower end of confidence interval = $m-z *\frac{psd}{ \sqrt{n} }$
Using the values, we get:
Lower end of confidence interval= $123.6-2.327* \frac{36.8}{ \sqrt{22}}=105.34$
Upper end of confidence interval = $m+z *\frac{psd}{ \sqrt{n} }$
Using the values, we get:
Upper end of confidence interval= $123.6+2.327* \frac{36.8}{ \sqrt{22}}=141.86$

Thus the 98% confidence interval will be (105.34, 141.86)

Part 4) Comparison of Confidence Intervals
The 90% confidence interval is: (110.69, 136.51)
The 95% confidence interval is: (108.22, 138.98)
The 98% confidence interval is: (105.34, 141.86)

As the level of confidence is increasing, the width of confidence interval is also increasing. So we can conclude that increasing the confidence level increases the width of confidence intervals.

3 0

3 years ago

Just need the answer for a and b

34kurt

Answer:

2⁵× 2ˣ = 256

x= 3

(1/3)² (1/3)ˣ = 1/729

x= 4

Step-by-step explanation:

2⁵× 2ˣ = 256

x= 3

use Product Rule: xᵃxᵇ=xᵃ⁺ᵇ

convert both sides to the same base.

2⁵⁺ˣ = 2⁸

cancel the base of 2 on both sides.

5+x=8

subtract 5 from both sides.

x=8-5

simplify 8-5 3.

x=3

(1/2)² (1/3)ˣ = 1/729

x = 4

use division distributive property: (x/y)ᵃ=xᵃ/yᵃ

i hope this helped i didn't feel like typing the rest out though lol :(

5 0

2 years ago

If a product of three numbers is 3150, two of the numbers are 14,15. Find the third number

kogti [31]

Answer:

15

proof on pic......................

3 0

3 years ago