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3 years ago

Can someone please explain step by step on the problem so I could get the answer! If so I’ll mark you brainliest

Mathematics

2 answers:

Tasya [4]3 years ago

5 0

Answer:

Rewrite 4 as a fraction with a denominator of 11 (make it easier when subtracting).

3 11/11 - 2 7/11

Subtract the fraction part first and then the whole number part.

1 4/11

umka21 [38]3 years ago

3 0

15/11 is the answer

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In the past year, Hans watched 38 movies that he thought were very good. He watched 95 movies over the whole year. Of

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Answer:

40%

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38×100=3800÷95=40

40%×95=38

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4 years ago

If a ratio is 4:5, how many parts are there in total?

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3 years ago

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What is the slope of the line with the equation of y = −

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4 years ago

Find all values of x for which the series converges. (Enter your answer using interval notation.) [infinity] 9 x − 7 9 n n = 0 F

makkiz [27]

Answer:

The series converges to $\frac{1}{1-9x}$ for $\frac{-1}{9} < x < \frac{1}{9}$

Step-by-step explanation:

Given the series is $\sum_{n=0}^{\infty} 9^n x^n$

We have to find the values of x for which the series converges.

We know,

$\sum_{n=0}^{\infty} ar^{n-1}$ converges to (a) / (1-r) if r < 1

Otherwise the series will diverge.

Here, $\sum_{n=0}^{\infty} 9^n x^n = \sum_{n=0}^{\infty} (9x)^{n}$ is a geometric series with |r| = | 9x |

And it converges for |9x| < 1

Hence, the given series gets converge for $\frac{-1}{9} < x < \frac{1}{9}$

And geometric series converges to $\frac{a}{1-r}$

Here, a = 1 and r = 9x

Therefore, $\frac{a}{1-r} = \frac{1}{1-9x}$

Hence, the given series converges to $\frac{1}{1-9x}$ for $\frac{-1}{9} < x < \frac{1}{9}$

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3 years ago