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3 years ago

In the past year, Hans watched 38 movies that he thought were very good. He watched 95 movies over the whole year. Of

Mathematics

1 answer:

Len [333]3 years ago

8 0

Answer:

40%

Step-by-step explanation:

38×100=3800÷95=40

40%×95=38

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Find the indicated probability.

LekaFEV [45]

Using it's concept, it is found that there is a 0.152 = 15.2% probability that they are both Democrats.

<h3>What is a probability?</h3>

A probability is given by the <u>number of desired outcomes divided by the number of total outcomes</u>.

Two voters are selected, each with 39% probability of being Democrats, hence the probability of both being Democrats is given by:

p = (0.39)² = 0.152.

0.152 = 15.2% probability that they are both Democrats.

More can be learned about probabilities at brainly.com/question/24372153

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6 0

2 years ago

What six over eight in simplest form

Lilit [14]

3/4

6 divided by 2 = 3

8 divided by 2 = 4

3 0

4 years ago

Plz help

katen-ka-za [31]

Answer:

The slope is -3/4 because it rises goes down 3 and runs 4. the Y-intercept or where the line meets the y line is 3

Step-by-step explanation:

5 0

3 years ago

Which of the following is an identity? Also, please include an explanation.

Lerok [7]

$cot\theta= \frac{ cos \theta}{ sin \theta } \\ sec\theta = \frac{1}{ cos \theta } \\ \\ \\ sin \theta cot\theta sec\theta \\ = sin \theta \cdot \frac{ cos \theta}{ sin \theta } \cdot \frac{1}{ cos \theta } \\ = \frac{ sin \theta}{ sin \theta } =1 \\$

sinθcotθsecθ = 1

6 0

3 years ago

Which of the following functions are solutions of the differential equation y'' + y = 3 sin x? (select all that apply)

DiKsa [7]

Answer:

Step-by-step explanation:

We must compute the derivatives and check if the equation is satisfied.

A. $y'=(3\sin x)'=3\cos x$ . Differentiate again to get $y''=(3\cos x)'=-3\sin x$ , then $y''+y=-3\sin x+3\sin x=0\neq 3\sin x$ so this choice of y doesn't solve the equation.

B. $y'=3\sin x+3x\cos x-5\cosx +5x\sin x=(5x+3)\sin x+(3x-5)\cos x$ and $y''=5\sin x+(5x+3)\cos x+3\cos x-(3x-5)\sin x=(10-3x)\sin x+(5x+6)\cos x$ , then $y''+y=10\sin x+6\cos x\neq 3\sin x$ so y is not a solution

C. $y'=\frac{-3}{2}\cos x+\frac{3}{2}x\sin x$ hence $y''=\frac{3}{2}\sin x+\frac{3}{2}\sin x+\frac{3}{2}x\cos x=3\sin x+\frac{3}{2}x\cos x$ . Then $y''+y=3\sin x+\frac{3}{2}x\cos x-\frac{3}{2}x\cos x=3\sin x$ so y is a solution.

D. $y'=-3\sin x$ and $y''=-3\cos x$ , then $y''+y=0$ thus y isn't a solution

E. $y'=\frac{3}{2}\sin x+\frac{3}{2}x\cos x$ hence $y''=\frac{3}{2}\cos x+\frac{3}{2}\cos x-\frac{3}{2}x\sin x=3\cos x-\frac{3}{2}x\cos x$ . Then $y''+y=3\cos x-\frac{3}{2}x\cos x-\frac{3}{2}x\cos x=3\cos x\neq 3\sin x$ then y is not a solution.

3 0

3 years ago