Answer:
1/2 wWBb , White wool and brown eyes.
1/2 wWbb , White wool and blue eyes.
Explanation:
White wool (W) is dominant over black wool (w).
Brown eyes (B) is dominant over blue eyes (b).
A sheep with black wool (ww) and brown eyes (Bb) is crossed with a sheep with white wool (WW) and blue eyes (bb).
<h3>wwBb x WWbb</h3>
If there is independent assortment between genes, the genotypes of the first parent's gametes will be wB and wb. The gametes of the second parent can only be Wb.
<u>The resulting offspring will be:</u>
- 1/2 wWBb , White wool and brown eyes.
- 1/2 wWbb , White wool and blue eyes.
Answer:
Option 1, No. The highest frequency of heterozygotes under Hardy-Weinberg equilibrium is 0.5
Explanation:
As per Hardy Weinberg’s equilibrium principle, the maximum frequency of heterozytotic individuals occur only when half of the population is dominant and recessive homozygous.
In other way when the sum of frequency of dominant and recessive species is equal to 0.5, only then the frequency of heterozygotes is maximum which in any case would not be higher than 0.5.
Hence, option 1 is correct
<span>The twisted ladder shape of DNA is called a double </span>helix.
