Question

Which describes the graph of y = (x - 4)2 - 1?

Answer 1

Answer:

A

Step-by-step explanation:

The equation of a parabola in vertex form is

y = a(x - h)² + k

where (h, k ) are the coordinates of the vertex and a is a multiplier

y = (x - 4)² - 1 ← is in vertex form

with vertex = (h, k ) = (4, - 1 )

• If a > 0 then the graph opens up

• If a < 0 then the graph opens down

Here a = 1 > 0 then graph opens up

Thus option A

Answer 2

C opens up with a vertex at (-4,-1)