The circumfrence of a circle is

diamter is 2r (
Two times the radius )
So you would now have

\pi = 3.14
so
(3.14)(5) = 15.7
The answer is B, 15.7 In you question you wrote it as C
Answer:

Step-by-step explanation:
Given

Required
Write as:

In
, the coefficient of x is -6
Divide by 2: -3
Square: 9
Add 9 - 9 to the above equation

Split to 2
![f(x) = [3x^2 - 6x +9]-[9- 6]](https://tex.z-dn.net/?f=f%28x%29%20%3D%20%5B3x%5E2%20-%206x%20%2B9%5D-%5B9-%206%5D)
![f(x) = [3x^2 - 6x +9]-[3]](https://tex.z-dn.net/?f=f%28x%29%20%3D%20%5B3x%5E2%20-%206x%20%2B9%5D-%5B3%5D)
Factorize:
![f(x) = [3x^2 - 3x -3x+9]-[3]](https://tex.z-dn.net/?f=f%28x%29%20%3D%20%5B3x%5E2%20-%203x%20-3x%2B9%5D-%5B3%5D)
![f(x) = [3x(x - 1) -3(x-1)]-[3]](https://tex.z-dn.net/?f=f%28x%29%20%3D%20%5B3x%28x%20-%201%29%20-3%28x-1%29%5D-%5B3%5D)
![f(x) = [(3x - 3)(x-1)]-[3]](https://tex.z-dn.net/?f=f%28x%29%20%3D%20%5B%283x%20-%203%29%28x-1%29%5D-%5B3%5D)
Factorize 3x - 3
![f(x) = [3(x - 1)(x-1)]-[3]](https://tex.z-dn.net/?f=f%28x%29%20%3D%20%5B3%28x%20-%201%29%28x-1%29%5D-%5B3%5D)
![f(x) = 3(x - 1)^2-[3]](https://tex.z-dn.net/?f=f%28x%29%20%3D%203%28x%20-%201%29%5E2-%5B3%5D)

Answer:
Step-by-step explanation:
This is a right triangle problem. The reference angle is x, the side opposite the reference angle is 32, and the hypotenuse is 58. The trig ratio that relates the side opposite a reference angle to the hypotenuse is the sin. Filling in accordingly:

Because you are looking for a missing angle, you will use your 2nd button and then the sin button to see on your display:

Within the parenthesis enter the 32/58 and you'll get your angle measure. Make sure your calculator is in degree mode, not radian mode!!!
<h2>Answer:</h2><h2>2³ * 2⁷ = 2³⁺⁷ = 2¹⁰</h2>
Looking at the answers only 5 (5!) and 8! will have GCF as 5! It is given that GCD of two numbers is 5!
5 and 10
5 and 15
10 and 15