Answer:
0.818335 ≤ p ≤ 0.86366
Step-by-step explanation:
Given that:
Sample size (n) = 1000
Positive lung cancer = 841
n(p) = 841, p(p) = 841/1000 = 0.841
n(1 - p) = 1000 - 841 = 159
1 - p = 0.159
95% confidence interval
For a 95% confidence interval : z = 1.96
P ± z√p(1-p) / n
0.841 ± 1.96 * √0.841(0.159) / 1000
0.841 - (1.96 * 0.0115636) = 0.818335344
0.841 + (1.96 * 0.0115636) = 0.863664656
0.818335 ≤ p ≤ 0.86366
Answer: 818.4
Step-by-step explanation:
Using the area of a sector formula, we get the area of the entire sector is
.
Using the formula
, we get the area of the triangle is
.
So, the area of the shaded sector is 
<h3>One possible set for the base area and height of the pyramid is 570 cm and 1 cm respectively</h3><h3>Other possible set for the base area and height of the pyramid is 285 cm and 2 cm respectively</h3>
<em><u>Solution:</u></em>
<em><u>The volume of rectangular pyramid is given as:</u></em>

Given that,
<em><u>Rectangular pyramid has a volume of 190 cubic centimeters</u></em>
<em><u></u></em>
<em><u></u></em>
<em><u>Substitute, base area = 570 and height = 1</u></em>
Then we get,

Thus one possible set for the base area and height of the pyramid is 570 cm and 1 cm respectively
<em><u>Substitute, base area = 285 and height = 2</u></em>

Thus other possible set for the base area and height of the pyramid is 285 cm and 2 cm respectively
Answer:
A 20
Step-by-step explanation:
Given
Phone Battery Life (hours)
A 20
B 25
C 10
D 18
8.45% of the battery life of each mobile phone is used in a day by a typical user
Calculating Hours of battery life in a day for each mobile
A 20
Battery life for A =
hours
B 25
Battery life for B =
hours
C 10
Battery life for C =
hours
D 18
Battery life for D =
hours
Therefor Mobile phone A 20 uses a total of 1.69 hours of battery life in a day
Raise aquarium is 6000 inches
Randle aqarium is 5760 inches
Raise has the bigger aquarium by 240 inches