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Verdich [7]
3 years ago
7

Which angles measure is equal to the sum of the measure

Mathematics
1 answer:
Afina-wow [57]3 years ago
3 0

Answer:

The measure of an exterior angle of a triangle is equal to the sum of the measures of the two non-adjacent interior angles of the triangle.

<h2>Please mark me as brainliest </h2>

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Which expression represents the prime factorization of 108?
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Answer: A. 3 x 3 x 3 x 4

Step-by-step explanation: 3 x 3 = 9 x 3 = 27 x 4 = 108

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\huge\boxed{Solution=B,(3,2)}

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Dan drew the line of best fit on the scatter plot shown below: A graph is shown with scale along x axis from 0 to 10 at incremen
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     0, 3
-   10, 15
= -10, -12
therefore, the slope is 6/5, and the intercept (c) is as supplied, 3.
the equation, y=mx+c or y = a + bx, can be applied here where m or b = 6/5, and a or c = 3.

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To test this, you can put in y = 10(6/5)+3, which spits out y = 15. This way we know it *should* work.

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3 years ago
A group of friends went to a sporting event. It cost $32 for each of them what was the total cost for all of them to get in
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3 years ago
What is the area of the rectangle? shoe your work! do not round anything until the very end and round your final answer to the t
weeeeeb [17]

Answer:

The area of the rectangle is 42 units^2

Step-by-step explanation:

we know that

The area of rectangle is equal to

A=LW

In this problem

AB=DC

BC=AD

see the attached figure with letters to better understand the problem

we have that

L=BC\\W=AB

the formula to calculate the distance between two points is equal to

d=\sqrt{(y2-y1)^{2}+(x2-x1)^{2}}

we have the points

A(2,-1),B(5,2),C(12,-5),D(9,-8)

<em>Find out the distance BC</em>

we have

B(5,2),C(12,-5)

substitute in the formula

d=\sqrt{(-5-2)^{2}+(12-5)^{2}}

d=\sqrt{(-7)^{2}+(7)^{2}}

d_B_C=\sqrt{98}\ units

<em>Find out the distance AB</em>

we have

A(2,-1),B(5,2)

substitute in the formula

d=\sqrt{(2+1)^{2}+(5-2)^{2}}

d=\sqrt{(3)^{2}+(3)^{2}}

d_A_B=\sqrt{18}\ units

<em>Find out the area</em>

A=(L)(W)

we have

L=d_B_C=\sqrt{98}\ units

W=d_A_B=\sqrt{18}\ units

substitute

A=(\sqrt{98})(\sqrt{18})=42.0\ units^2

4 0
4 years ago
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