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3 years ago

In class, there are 12 girls and 11 boys. Write each ratio 3 ways.

Mathematics

1 answer:

PilotLPTM [1.2K]3 years ago

4 0

12/11, 12:11, 12 to 11

11/12, 11:12, 11 to 12

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Four points partition the directed line segment from A to B. • Point P partitions the directed line segment from A to B into a 3

Alecsey [184]

Answer:

S is closest to B.

Step-by-step explanation:

Given a directed line segment from point A to B.

Point P divides the line A to B in a ratio 3:4.

Point Q divides the line A to B in a ratio 4:3.

Point R divides the line A to B in a ratio 2:5.

Point S divides the line A to B in a ratio 5:2.

To find:

The point which is closest to the point B.

Solution:

Here, to find the point closest to B we need to find the distances PB, QB, RB and SB.

We can see the sum of ratio 3:4, 4:3, 2:5 and 5:2 is 7.

Let the distance between A and B be 7 units.

Now, the distances can be found easily.

$PB = \dfrac{4}{7}\times 7 = 4\ units$

$QB = \dfrac{3}{7}\times 7 = 3\ units$

$RB = \dfrac{5}{7}\times 7 = 5\ units$

$SB = \dfrac{2}{7}\times 7 = 2\ units$

The point which has the minimum distance from point B, will be nearest to B.

We can clearly observe that SB is the minimum distance.

Therefore, <em>S is closest to B</em>.

4 0

3 years ago

Read 2 more answers

Joel scores in 80% of his games. His team is starting the playoffs, and if they make it to the state championship, they will hav

Fittoniya [83]

Answer:

Step-by-step explanation:

4 out of 5 games is 80%:

So if we know, as a rule that "Joel scores in 80% of his games.", the probability that he will score in 80% of his games is 1 - that is, we know it for sure

100% sure

4 0

3 years ago

Read 2 more answers

S<br>solve for X<br>2x - Px = 5

maxonik [38]

Answer:

$2x - P = 5 \\ x(2 - P) = 5 \\ \boxed{x = \frac{5}{(2 - P)} }$

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3 years ago

Jamal went to the post office to buy stamps and large envelopes. Each stamp costs the same amount, and each large envelope costs

nekit [7.7K]

Answer:

Step-by-step explanation:

i chose .95 cents!

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3 years ago

A town is planning a playground. It wants to fence in a rectangular space using an existing wall. What is the greatest area it c

777dan777 [17]

Answer:

1250 $ft^{2}$

Step-by-step explanation:

We are given that the playground is fenced on three sides of the playground and the four side has an existing wall.

Let the length of the rectangle be 'X' feet and width be 'Y' feet.

As the fencing is done using 100 feet of fence. We get the relation between the sides and the fence as, X + 2Y = 100.

As, X + 2Y = 100 → X = 100 - 2Y

Now, the area of the rectangle = XY = X × ( 100 - 2Y ).

i.e Area of the rectangle = $-2Y^{2} +100Y$ .

The general form of a quadratic equation is $y=ax^{2}+bx+c$ .

The maximum value of a quadratic equation is given by $x=\frac{-b}{2a}$ .

Therefore, the greatest value of $-2Y^{2} +100Y$ is at Y = $\frac{-100}{2 \times -2}$ = $\frac{-100}{-4}$ = 25.

Thus, Y = 25 and X = 100 - 2Y → X = 100 - 2 × 25 → X = 50.

Hence, the area of the rectangle is XY = 50 × 25 = 1250 $ft^{2}$ .

3 0

3 years ago