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Anon25 [30]
2 years ago
14

In class, there are 12 girls and 11 boys. Write each ratio 3 ways.

Mathematics
1 answer:
PilotLPTM [1.2K]2 years ago
4 0
12/11, 12:11, 12 to 11

11/12, 11:12, 11 to 12
You might be interested in
Solve the inequality -10w _< 20
Dvinal [7]

Step-by-step explanation:

  • -10w<u><</u><u> </u>20
  • w<u><</u><u> </u>20/-10
  • w<u><</u><u> </u>-2

hope it helps

<h2>stay safe healthy and happy...</h2>
8 0
2 years ago
The students at a High School earned money for an international animal rescue foundation. 82 seniors earned an average $26.75 pe
Anon25 [30]

Answer: A. $16.13

Step-by-step explanation:

Total students = 82+74+96+99 =351

Sum of earnings of 82 seniors  = $26.75  x 82= $2193.5

Sum of earnings of 74 juniors  = $12.25 x 74 = $906.5

Sum of earnings of 96 sophomores  = $15.50  x 96 = $1488

Sum of earnings of 99 freshmen  =  $10.85 x 99 = $1074.15

Total earnings =  $2193.5  + $906.5+  $1488 +$1074.15

= $5662.15

(Total earnings) ÷ (Total students )

= $5662.15÷ 351

= $16.13

4 0
3 years ago
Simplify (-5) + (-4) + (7).<br> 0-2<br> 06<br> O<br> 8<br> 16
stich3 [128]

Answer:

- 2

Step-by-step explanation:

The question is - 5 + - 4 + 7

You do addition first.

-4 + 7 = 3

So now we have - 5 + 3

-5 + 3 = - 2

5 0
2 years ago
In a group of 42 students, 9 study both Art and Biology.
LUCKY_DIMON [66]
Answer:
The probability the student studies Art and
Biology is 0.2143.
Step-by-step explanation:
Denote the events as follows:
A = a students studies Art
B= a students studies Biology
The information provided is:
N = 42
n (An B) = 9
n (A' n B) = 10
n (A' n B') =7
Then the number of students who study Art
but not Biology is:
n(An B') = N -n (An B) -n (A' nB) - n (A'n B')
= 42 - 10 - 7 - 9
= 16
The number of students who study Art but
not Biology is 16.
Compute the probability the student studies
Art and Biology as follows:
P(ANB)
n(ANB)
= 0.2143
Thus, the probability the student studies Art
and Biology is 0.2143.
3 0
2 years ago
The quantity a varies directly with b and c and inversely with dThe quantity d is tripledWhich of the following must be true for
EastWind [94]

Answer:

We have the next relation:

A = (b*d)/c

because we have direct variation with b and d, but inversely variation with c.

Now, if we have 3d instead of d, we have:

A' = (b*(3d))/c

now, we want A' = A. If b,c, and d are the same in both equations, we have that:

3bd/c = b*d/c

this will only be true if b or/and d are equal to 0.

If d remains unchanged, and we can play with the other two variables we have:

3b'd/c' = bd/c

3b'/c' = b/c

from this we can took that: if c' = c, then b' = b/3, and if b = b', then c' = 3c.

Of course, there are other infinitely large possible combinations that are also a solution for this problem where neither b' = b or c' = c

6 0
2 years ago
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