Sorry I don’t know the answer is just needed a point to get my question answered
f(h(x))= 2x -21
Step-by-step explanation:
f(x)= x^3 - 6
h(x)=\sqrt[3]{2x-15}
WE need to find f(h(x)), use composition of functions
Plug in h(x)
f(h(x))=f(\sqrt[3]{2x-15})
Now we plug in f(x) in f(x)
f(h(x))=f(\sqrt[3]{2x-15})=(\sqrt[3]{2x-15})^3 - 6
cube and cube root will get cancelled
f(h(x))= 2x-15 -6= 2 x-21
Answer:
Step-by-step explanation:
Here's analyses of the other options:
Option A. You can clearly see that is not defined for , so the function doesn't have the same domain as that of , hence can't be the answer.
Option C. By the definition of absolute value, we know that , this is the same function, hence not the answer.
Option D. This is just shifted one unit to the right, not flipped.
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Answer:
i like yo cut g, are there options or not?
Step-by-step explanation:
