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Firlakuza [10]
2 years ago
15

Solve the equation. 6 = 3s what is s?????

Mathematics
2 answers:
swat322 years ago
6 0
The variable s I equal to the number 2
kupik [55]2 years ago
4 0
Answer:
s = 2

Steps:
To figure out what s is equal to you need to get it alone. You can do this by dividing 3 on both sides to get s alone.

6/3 = 3s/3

2 = s
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Answer:

The answer is 88

Step-by-step explanation:

I think the answer is 88 because if you do 96+ 84 it equals 180 and if you do 92+ 88 it equals 180 as well and that is how you know it is right

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7 0
2 years ago
Read 2 more answers
Six diminished by twice a number is ten
alina1380 [7]
6-2a = 10
6-10 = 2a
a = -2
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2 years ago
Please help me with 20 through 22 please I really appreciate it! Thank you very much!
Ivahew [28]

Answer:

20. 2x+y

21. 4

22. x+y

Step-by-step explanation:

20. <u>9</u><u>x</u><u>+</u><u>2</u><u>y</u><u> </u>- <u>x-2</u><u>y</u><u> </u><u> </u> find your LCM

4 4

=<u>(</u><u>9</u><u>x</u><u>+</u><u>2</u><u>y</u><u>)</u><u>-</u><u>(</u><u>x-2y</u><u>)</u><u> </u> clear bracket

<u> </u><u> </u><u> </u><u> </u><u> </u><u> </u><u> </u><u> </u><u> </u><u> </u><u> </u><u> </u><u> </u><u> </u><u> </u><u> </u><u> </u><u> </u><u> </u>4

=<u>9</u><u>x</u><u>+</u><u>2</u><u>y</u><u>-</u><u>x</u><u>+</u><u>2</u><u>y</u><u> </u> collect terms

4

=<u>9</u><u>x</u><u>-</u><u>x</u><u>+</u><u>2</u><u>y</u><u>+</u><u>2</u><u>y</u>

<u> </u> 4

=<u>8</u><u>x</u><u>+</u><u>4</u><u>y</u><u> </u> factorize

<u> </u><u> </u><u> </u><u> </u><u> </u><u> </u><u> </u><u> </u><u> </u><u> </u><u> </u><u> </u>4

=<u>4</u><u>(</u><u>2</u><u>x</u><u>+</u><u>y</u><u>)</u>

<u> </u><u> </u> 4

=2x+y

with this, you will understand the following

21. <u>4</u><u>x</u> + <u>8</u><u>y</u>

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22. <u>2</u><u>x</u><u>-</u><u>y</u><u> </u>+ <u>2</u><u>x</u><u>+</u><u>5</u><u>y</u>

4 4

=<u>2</u><u>x</u><u>-</u><u>y</u><u>+</u><u>2</u><u>x</u><u>+</u><u>5</u><u>y</u>

4

=<u>4</u><u>x</u><u>+</u><u>4</u><u>y</u>

4

=<u>4(</u><u>x</u><u>+</u><u>y</u><u>)</u>

4

=x+y

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expeople1 [14]

Answer:

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QveST [7]
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