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Slav-nsk [51]
2 years ago
6

Please answer CORRECTLY !!!!! Will mark brainliest !!!!!!!

Mathematics
2 answers:
natita [175]2 years ago
5 0

Answer: 1. a

2. -75

Step-by-step explanation:

stepladder [879]2 years ago
4 0

Answer:

1.A 2.-75

Step-by-step explanation:

I solved it and got those awnsers

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The FBI wants to determine the effectiveness of their 10 Most Wanted list. To do so, they need to find out the fraction of peopl
Zinaida [17]

Answer:

Step-by-step explanation:

Hello!

The variable of interest is X: number of criminals in the 10 Most Wanted list that were captured in a sample of 523 suspected criminals.

The number of criminals that were captured is 172 out of 523.

To calculate the sample proportion, you have to divide the number of success, in this case, captured criminals, by the total number of criminals sampled:

^p= 172/523= 0.329

I hope this helps!

7 0
3 years ago
Ben and Ella are filling goodie bags for a party. Each goodie bag needs an eraser, a bubble wand, and a few candy bar bites. Ben
maxonik [38]

Answer:

Ben

Step-by-step explanation:

25 goodies = 20 minutes

27 goodies = 24 minutes

Let's use ratio, divide both of them by their minute

25/20 = 20/20

27/24 = 24/24

1.25 goodies = 1 minute

1.12 goodies = 1 minute

1.25 is bigger than 1.12.

7 0
3 years ago
-2 1/5 (10x - 4.4) - 0.32
Semenov [28]
−42x+ 18.16

I think !!
6 0
2 years ago
Helppppppppp pleaseeeeeee fasttttt
topjm [15]
I think it’s 104,974
Because PEMDAS,
so first deal with exponents and 3 to the fourth power is 81. 6 to the fourth power is 1,296.
Next in PEMDAS is multiplication and division, so 1,296 times 81 is 104,976. Then 4 divided by 2 is 2.
Finally comes subtraction, 104,976 minus 2 = 104,974
5 0
3 years ago
Read 2 more answers
The number of flaws per square yard in a type of carpet material varies with mean 1.4 flaws per square yard and standard deviati
oksian1 [2.3K]
According to the Central Limit Theorem, the distribution of the sample means is approximately normal, with the mean equal to the population mean (1.4 flaws per square yard) and standard deviation given by:
\frac{\sigma}{ \sqrt{n} }=\frac{1.2}{ \sqrt{178} }=0.09
The z-score for 1.5 flaws per square yard is:
z=\frac{1.5-1.4}{0.09}=1.11
The cumulative probability for a z-score of 1.11 is 0.8665. Therefore the probability that the mean number of flaws exceeds 1.5 per square yard is
1 - 0.8665 = 0.1335.
6 0
3 years ago
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