Can someone help me with this please?
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The population function of the Western Lowland Gorillas can either represent population growth or population decay
<h3>How to model the population</h3>The question is incomplete, as the resources to model the population of the Western Lowland Gorillas are not given.
So, I will give a general explanation to solve the question
A population function can be represented as:
Where:
- The initial population of the Western Lowland Gorillas is represented by (a)
- The rate at which the population changes is represented by (r)
- The number of years since 2022 is represented by (x)
- The population in x years is represented by (y)
From the question, we understand that the population of the Western Lowland Gorillas decreases.
This means that the rate of the function would be an exponential decay i.e. 1 -r
Take for instance:
By comparison.
a = 2000 and 1 - r = 0.98
The above function can be used to model the population of the Western Lowland Gorillas
Read more about exponential functions at:
Answer:
which is the same as writing 56y^2m
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Explanation:
Let's focus on the coefficients 8 and 7 for now.
To find the LCM of those values, list out the multiples. Circle the smallest number that can be found in both sets at the same time.
- multiples of 8 are: 8, 16, 24, 32, 40, 48, 56, 64, ...
- multiples of 7 are: 7, 14, 21, 28, 35, 42, 49, 56, 63, ....
We see that 56 is the LCM of 7 and 8.
Or you could use this shortcut
LCM = (x*y)/GCF
where x and y are the two numbers. The mention of "GCF" refers to the GCF of x and y. In this case, the GCF is 1 so,
LCM = (x*y)/GCF = (8*7)/1 = 8*7 = 56.
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Once we determine that, we look at the variable terms now.
The y^2 and m will be tacked onto the 56 to arrive at the final answer 56y^2m
This is because y and m are the unique variables, and we go for the highest exponent of each. It's similar to the LCM formula used earlier.