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2 years ago

Factor x^2+5x+2 trinomial

Mathematics

1 answer:

valina [46]2 years ago

5 0

Answer:

You cannot factor this.

Step-by-step explanation:

Nothing can multiply, to equal 2 and add up to 5.

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10. Amina is currently twice as old as her younger brother,

maks197457 [2]

Answer:

When Amina is 18. Saad would be;

k. 14

Step-by-step explanation:

Let "x" represent Anita's current age and let "y" represent Saad's current age, we have;

Anita's age = 2 × Saad's age

Therefore;

x = 2 × y...(1)

In 4 years, we will get;

x + 4 = 1.5 × (y + 4)...(2)

Substituting the value of x in equation (1) into equation (2), we get;

2·y + 4 = 1.5·y + 1.5 × 4 = 1.5·y + 6

2·y + 4 = 1.5·y + 6

2·y - 1.5·y = 6 - 4 = 2

0.5·y = 2

y = 2/0.5 = 4

Saad's current age = y = 4 years

From equation (1), we have;

x = 2 × y = 2 × 4 = 8

Amina's current age = x = 8 years

When Amina is 18, we have;

18 = 10 + 8 = 10 + x

Therefore, Amina would be 18 in 10 years time from now, from which we have;

Saad would be 10 years + y = 10 years + 4 years = 14 years in 10 years from now

Therefore, when Amina would be 18 years in 10 years from now Saad would be 14 years.

6 0

3 years ago

A rectangular prymaid is sliced to its base as shown in the figure.

Furkat [3]

The answer is D: rectangle

7 0

3 years ago

GREYUIT [131]

Answer:

$175\ in^{2}$

Step-by-step explanation:

step 1

Find the scale factor

we know that

If two figures are similar, then the ratio of its volumes is equal to the scale factor elevated to the cube

Let

z----> the scale factor

x----> volume of the larger solid

y----> volume of the smaller solid

$z^{3}=\frac{x}{y}$

we have

$x=125\ in^{3}$

$y=27\ in^{3}$

substitute

$z^{3}=\frac{125}{27}$

$z=\frac{5}{3}$

step 2

Find the surface area of the larger solid

we know that

If two figures are similar, then the ratio of its surface areas is equal to the scale factor squared

Let

z----> the scale factor

x----> surface area of the larger solid

y----> surface area of the smaller solid

$z^{2}=\frac{x}{y}$

we have

$z=\frac{5}{3}$

$y=63\ in^{2}$

substitute

$(\frac{5}{3})^{2}=\frac{x}{63}$

$x=\frac{25}{9}*63=175\ in^{2}$

3 0

3 years ago

PLEASE HELP ME!! (50 COINS) (i rlly need help so im giving coins away PLEASE ANSWER IMMEDIATELY!!!)

Archy [21]

Hello from MrBillDoesMath!

Answer:

4( x + 1.5)^2 + 0

Discussion:

4x^2 + 12x + 9 = => factor "4" from first 2 terms

4 (x^2 + 3x) + 9 = => complete the square, add\subtract (1.5)^2

4(x^2 + 3x + (1.5)^2) - 4 (1.5)^2 + 9 =

4 ( x + 1.5)^2 + ( 9 - 4(1.5)^2) = => as (1.5)^2 = 2.25

4 ( x + 1.5)^2 + ( 9 - 4(2.25)) = => as 4 ( 2.25) = 9

4 ( x+ 1.5)^2 + 0

Thank you,

MrB

5 0

2 years ago

The physical plant at the main campus of a large state university recieves daily requests to replace florecent lightbulbs. The d

kozerog [31]

Answer: 49.85%

Step-by-step explanation:

Given : The physical plant at the main campus of a large state university recieves daily requests to replace florecent lightbulbs. The distribution of the number of daily requests is bell-shaped ( normal distribution ) and has a mean of 61 and a standard deviation of 9.

i.e. $\mu=61$ and $\sigma=9$

To find : The approximate percentage of lightbulb replacement requests numbering between 34 and 61.

i.e. The approximate percentage of lightbulb replacement requests numbering between 34 and $34+3(9)$ .

i.e. i.e. The approximate percentage of lightbulb replacement requests numbering between $\mu$ and $\mu+3(\sigma)$ . (1)

According to the 68-95-99.7 rule, about 99.7% of the population lies within 3 standard deviations from the mean.

i.e. about 49.85% of the population lies below 3 standard deviations from mean and 49.85% of the population lies above 3 standard deviations from mean.

i.e.,The approximate percentage of lightbulb replacement requests numbering between $\mu$ and $\mu+3(\sigma)$ = 49.85%

⇒ The approximate percentage of lightbulb replacement requests numbering between 34 and 61.= 49.85%

4 0

2 years ago