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Burka [1]
3 years ago
13

Ms. Henning wants to purchase 30 calculators for her math class. Calculators cost $14 each. Me. Henning currently has $300 in he

r account to spend on the calculators. How much more money does she need?
Mathematics
1 answer:
KATRIN_1 [288]3 years ago
8 0

Answer:

She needs 120 more dollars in order to purchase the calculators for her math class

Step-by-step explanation:

In order to solve this you have to find how much money 30 calculators are worth (30*14.00=420) which when subtracted from the amount she has in her account, (300) you can then subtract 420-300 to give you the answer of $120 more dollars

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6 times what is 36 <br> please answer in a correct fashion
atroni [7]

Answer:

6

Step-by-step explanation:

36/6=6

Hope this helps <3

8 0
3 years ago
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Write an equation of the line
Deffense [45]
(3,0) and (0,9)

Slope= (9-0)/(0-3)= -3

Line equals Y= -3x+9
4 0
3 years ago
13. Oscar's dog house is shaped like a tent. The slanted sides are both 5 feet
VashaNatasha [74]

Answer:

The height of the dog house = 4 feet.

Step-by-step explanation:

Given:

The shape of the dog house is like a tent.

The slant heights of the house is 5 feet.

The bottom of the house is 6 feet across.

To find the height of the dog house at its tallest point.

Solution:

On drawing the figure of the dog house in the shape of a tent, we find out that the tallest point would be at the midpoint of the bottom of the house.

Thus, we ave a right triangle, of which one leg = \frac{6\ ft}{2}=3\ ft and hypotenuse = 5\ ft

<em>Applying Pythagorean theorem to find the measure of the other leg which is the height of the house.</em>

Hypotenuse^2=Leg1^2+Leg2^2

Plugging in values.

5^2=3^2+Leg2^2

25=9+Leg2^2

Subtracting both sides by 9.

25-9=9-9+Leg2^2

16=Leg2^2

Taking square root both sides.

\sqrt{16}=\sqrt{Leg2^2}

4=Leg2

Thus, the height of the dog house = 4 feet.

6 0
4 years ago
A jar contains 10 ounces of gumdrops, 3 ounces of licorice bits, and 3 ounces of jelly beans. How many more ounces of jelly bean
Andrew [12]

Answer:

10 jelly beans.

Step-by-step explanation:

Let x be ounces of jelly beans.

We have been given that a jar contains 10 ounces of gumdrops, 3 ounces of licorice bits, and 3 ounces of jelly beans.

To make weight of jelly beans be 50% of total assortment, we will add x ounces of jelly beans to 3 so that it will be 50% of total assortment plus x. We can represent this information in an equation as:

3+x=\frac{50}{100}(10+3+3+x)

Let us solve for x.

3+x=0.50(16+x)

3+x=8+0.5x

3-3+x=8-3+0.5x

x=5+0.5x

x-0.5x=5+0.5x-0.5x

0.5x=5

\frac{0.5x}{0.5}=\frac{5}{0.5}

x=10

Therefore, 10 jelly beans must be added to make the assortment 50 percent jelly beans in weight.

Let us cross check our answer.

\frac{3+10}{3+3+10+10}=\frac{13}{26}=0.5=50\%

6 0
3 years ago
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