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2 years ago

Please solve look at photo plz plz plz plz pls plz plz

Mathematics

1 answer:

34kurt2 years ago

4 0

Answer:

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An inequality that has the following graphed solution

Alex787 [66]

Answer:

x > 5

Step-by-step explanation:

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3 years ago

Suppose that events a and b are mutually exclusive with p(a) = ½ and p(b) = ⅓.

irina1246 [14]

No, a & b are not independent if they're mutually exclusive.

Mutually exclusive means the two events cannot occur simultaneously. So if "a" happens "b" cannot. In contrast, two events are independent if the occurrence of one has no effect on the occurrence of the other.

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3 years ago

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lianna [129]

Answer:

Here is your answer

Step-by-step explanation:

B) 2x + 5 = 7

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C) 2x - y = 6

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D) 3y + 9 = 0

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3 years ago

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16. The graph of the function

den301095 [7]

$\text{Hello there!}\\\\\text{Our original equation is: y = 4x + 1}\\\\\text{Our new equation must be translated 3 units up}\\\\\text{This means that we're going up on the y axis, meaning that our}\\\text{"beginning point" will change}\\\\\text{Our beginning point is 1, so just add 3 to it}\\\\1+3 = 4\\\\\text{Put 4 as your beginning point in the equation:}\\\\y=4x+4\\\\\boxed{\text{Answer: y = 4x + 4}}$

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3 years ago

Someone please help me!!!!!

Katarina [22]

1. Answer (D). By the law of sines, we have $\frac{a}{\sin A}=\frac{b}{\sin B}=\frac{c}{\sin C}$ in any $\triangle ABC.$

2. Answer (C). The law of cosines, $c^2=a^2+b^2-2ab\cos C,$ accepts up to three sides and an angle as an input.

3. Answer (D). Although this triangle is right, we are not given enough information to uniquely determine its sides and angles - here, we need either one more side or one more angle.

4. Answer (D). Don't get tripped up by answer choice (C) - this is just a rearrangement of the statement of the law of cosines. In choice (D), the signs of $a^2$ and $2ab\cos C$ are reversed.

5. Answer (B). By the law of sines, we have $\frac{5}{\sin 40^\circ}=\frac{3}{\sin\theta}.$ Solving gives $\theta\approx \boxed{23^\circ},157^\circ.$ Note that this is the <em>ambiguous (SSA) case</em> of the law of sines, where the given measures could specify one triangle, two triangles, or none at all!

6. Answer (A). Since we know all three sides and none of the angles, starting with the law of sines will not help, so we begin with the law of cosines to find one angle; from there, we can use the law of sines to find the remaining angles.

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3 years ago