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3 years ago

Which graph represents the function h(x) = Ix| + 0.5?

Mathematics

1 answer:

Dmitrij [34]3 years ago

5 0

Answer: c

Step-by-step explanation: doesnt show a number so example lets say its 0

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Question is attached

Neporo4naja [7]

Answer: C

Step-by-step explanation: The standard equation is Ax + By = C

To solve for this, first solve for the slope: y2 - y1 / x2 - x1

0 - 5 / 4 - 0 = -5 / 4

Plug the slope and ordered pair of (0, 5) into the equation y - y1 = m(x - x1)

y - 5 = -5/4(x - 0)

Add 5 to both sides: y = -5/4x + 5

Subtract y and 5: -5 = -5/4x - y

Multiply the entire equation by 4: -20 = -5x - 4y

(or multiply entire equation by -4 to get 20 = 5x + 4y)

7 0

4 years ago

21 Maria sold small boxes of candy for $1 and

Anna35 [415]

Answer:

There where 10 more Small boxes sold than Large boxes.

Step-by-step explanation:

This is a typical question that can be solved by obtaining a system of two linear equations and solving for each variable.

In principle Linear Equations are algebraic expressions denoting a relationship between a Dependent variable $y$ and an Independent variable $x$ . In a system of Two Linear equations we have two equations of the same variable sets (thus Two Independent variables) so in this case both $y$ and $x$ will be variable terms.

Now with respect to the question and the given information, here our two Variable terms will be the small and the large boxes.

Given Information:

Small Boxes (lets call them $s$ ) cost $1 per box

Large Boxes (lets call them $l$ ) cost $4 per box
Total Number of Boxes sold is 30
Total Profit from sold Boxes is $60

Thus from the above we can obtain one equation denoting the Total Number of Boxes sold and one equation denoting the Total Profit from sold boxes, respectively, as follow:

$s+l=30$ Eqn(1): Total Number of Boxes

$1s+4l=60$ Eqn(2): Total Profit from sold boxes

Now we have a system of two linear equations which we can solve and find the number of small and large boxes, $s$ and $l$ respectively.

From Eqn(1) we see that

$s=30-l$ Eqn(3).

Plugging Eqn(3) in Eqn(2) we can solve for $l$ as:

$1(30-l)+4l=60$

$30-l+4l=60$ Factored out bracket

$3l=60-30$ Gather similar terms on each side and simplify

$3l=30$

$l=\frac{30}{3}$

$l=10$

Plugging in the value for $l=10$ in Eqn(3) we have

$s=30-10\\s=20$

So we know that they were 10 Large Boxes and 20 Small Boxes sold, thus to answer our question, there where 10 more Small boxes sold than Large boxes.

5 0

4 years ago

How many terms are in the expression 20x + 9y

Llana [10]

Two terms:

20x and 9y

3 0

4 years ago

Read 2 more answers

Some one help please

AleksAgata [21]

Answer:

subtracting 14 from sides of the number sentence

Step-by-step explanation:

14 + n = 84

Since 14 is being added to n, you need to subtract 14 from both sides to solve for n.

Answer: subtracting 14 from sides of the number sentence

3 0

3 years ago

Porfa ayuda :c t.t u.u

Orlov [11]

Answer: 40

ADE = 70 por suma de angulos interiores en triangulo ADE

En triangulos BDE y AED

AE=BE por dato

DE lado comun

AED= BED= 90

por tanto los triangulos son iguales por tener dos lados y el angulo comprendido respectivamente iguales

Luego ADE = BDE = 70 y AD=BD=BC por ser triangulos BDE y AED iguales

Luego triangulo BDC isosceles de base DC

ADE + BDE + BDC = 180 por suma de angulos consecutivos

BDC = 180 - 70 -70 = 40

Ф = BDC =BCD = 40 por ser angulos bases de un triangulo isosceles

4 0

4 years ago