Answer:
X=10
AB=12
BC=27
Solution: solving the algebraic equation we get x=10, then plug in x for each of the equations separately
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I must assume that you meant t=1 (not t=?1). If t=1, here's what we'd do:
1. Find the x and y values corresponding to t=1. They are:
x=(1)^7+1=2 and y=(1)^8+1=2. (Please note: write t^8 instead of t8, and write t^7 instead of t7.)
2. The slope of the tangent line to the graph is
dy/dt 8t^7+1
dy/dx = ---------- = ---------------- with 1 substituted for t
dx/dt 7t^6
Thus, dy/dx (at t=1) = 9/7
3. Now we have both a point (2,2) on the graph and the slope of the tangent line to the curve at that point: 9/7
4. The tangent line to the curve at (2,2) is found by using the point-slope formula:
y-y1 = m(x-x1)
which comes out to y-2 = 9/7(x-2), or 7y-14 = 9(x-2). You could, if you wished, simplify this result further (e. g., by solving for y in terms of x).
Answer:
Step-by-step explanation:
Given expression:
Convert this into equation and solve for k:
- 33 = k - 15
- k = 33 + 15
- k = 48
So the <u>value of k is 48</u>
Answer:
1) 270 degrees
2) pi/4 rad
Step-by-step explanation:
1.) For which value of theta is sine theta = negative 1?
Given
sintheta = -1
theta = arcsin(-1)
theta = -90degrees
Since sin is negative in the third and 4th quadrant
In the third quadrant, theta = 180 + 90 = 270degrees
In the fourth quadrant, theta = 360 - 90 = 270 degrees
Hence the required value of theta is 270degrees
2) Given the radius of the circle to be 1, the y axis value will also be 1 units
Opposite = 1
adjacent = 1
hyp = √1²+1²
hyp = √2
sin theta = opp/hyp
sin theta = 1/√2
theta = arccsin(1/√2)
theta = 45 degrees
Express in radians
45 degrees = pi/4 radians
Hence the required angle in the first quadrant is pi/4 rad
