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s2008m [1.1K]
2 years ago
5

The mass of the Earth is 5.972x10^24 kg. the mass of the moon is 7.3 x 10^22kg. find the total mass, in kg, of the Earth and the

moon. give your answer in standard form.
Mathematics
1 answer:
torisob [31]2 years ago
8 0

Answer:

6045000000000000000000000 kg.

Step-by-step explanation:

We have been given that the mass of Earth is 5.972\times10^{24} kg. The mass of the Moon is 7.3\times10^{22} kg.

To find the total mass we will add mass of Earth and Moon.

First of all let us convert the given masses in standard form.

5.972\times10^{24}=5972000000000000000000000  

7.3\times10^{22}=73000000000000000000000

5.972\times10^{24}+7.3\times10^{22}  

5972000000000000000000000+73000000000000000000000

6045000000000000000000000

Therefore, the mass of Earth and Moon is 6045000000000000000000000 kg.

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1. a line with a slope of 1/3 passes through the point (3, 6) . which point also lies on this line?
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1) Substituting into point-slope form, the equation of the line is y-6=⅓(x-3), which rearranges to:

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So, we can now substitute in the coordinates of each of the options to see which point lies on the line.

  1. 3 = ⅓(6) + 5 -> 3 = 7, which is false.
  2. 6 = ⅓(7) + 5 -> 6 = 22/3, which is false.
  3. -3 = ⅓(-3) + 5 -> -3 = 4, which is false.
  4. 3 = ⅓(-6) + 5 -> 3 = 3, which is true.

So, the answer is (4) (-6, 3)

2) Substituting into point-slope form, the equation of the line is y - 5 = ¾(x-2), which rearranges to:

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So, we can now substitute in the coordinates of each of the options to see which point lies on the line.

  1. 8 = 0.75(6)+3.5 -> 8 = 8, which is true.
  2. 9 = 0.75(5) + 3.5 -> 9 = 7.25, which is false.
  3. 1 = 0.75(-1) + 3.5 -> 1 = 2.75, which is false.
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Suppose that the scores on a reading ability test are normally distributed with a mean of and a standard deviation of . What pro
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Answer:

The proportion of individuals score at most 74 points on this test is 70%.

Step-by-step explanation:

The complete question is:

Suppose that the scores on a reading ability test are normally distributed with a mean of 70 and a standard deviation of 8. What proportion of individuals score at most 74 points on this test? Round your answer to at least four decimal places.

Solution:

Let <em>X</em> represent the scores on a reading ability test.

It is provided that X\sim N(70,8^{2}).

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P(X\leq 74)=P(\frac{X-\mu}{\sigma}\leq \frac{74-70}{8})

                 =P(Z

Thus, the proportion of individuals score at most 74 points on this test is 70%.

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