To find where on the hill the canonball lands
So 0.15x = 2 + 0.12x - 0.002x^2
Taking the LHS expression to the right and rearranging we have -0.002x^2 + 0.12x -
0.15x + 2 = 0.
So we have -0.002x^2 - 0.03x + 2 = 0
I'll multiply through by -1 so we have
0.002x^2 + 0.03x -2 = 0.
This is a quadratic eqn with two solutions x1 = 25 and x2 = -40 since x cannot be negative x = 25. The second solution y = 0.15 * 25 = 3.75
Answer:
0=2+3x+3/2
0=7/2+3x
-3x=7/2
divide by -3 on both sides
x=-7/6
hope this helps
Step-by-step explanation:
A
It is a first degree polynomial (aka linear because its highest power is 1) and it has two terms (2x and 8)
It does not have eight terms and is not a monomial (one term ie 3x^2)
The mapping rule for 90 degrees counterclockwise would be (-y,x). So if you had (x,y) it would transfer to (-y,x). Yours is wrong it should be (4,-3). Remember
-(-4) is 4 and -3 stays as -3.
Basically, memorize these mapping rules.
Hope this helped!
