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wel
2 years ago
12

I would like to say that I am one of the females in the world who are in love with the idea of love. Especially Ryan reynolds

Mathematics
1 answer:
Gwar [14]2 years ago
3 0

Answer:

That's cool.

Step-by-step explanation:

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dave and his sister picked out two pumpkins at the pumpkin patch. the pumpkins cost $0.47 per pound. davids pumpkin weighed 13.2
WINSTONCH [101]
Dave has 50 cents right now
4 0
3 years ago
Read 2 more answers
My homework is due soon, help!!
Fantom [35]

Answer:

50.24

Step-by-step explanation:

A = Area

Radius = 4 (The radius is half of the diameter

Diameter = 8

Pie = 3.14

A = (pie)r^2

A = (3.14)4^2

A = (3.14)16

A = 50.24

4 0
2 years ago
What is 12 more than 3 times a number?
sleet_krkn [62]

Answer:

I think it's 4 times 3 is the more number for 12.

4 0
2 years ago
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How do you factor 5x^2b^2 + 14xb^2 -3b^2
Monica [59]

Answer:

5b^2(x-0.2)(x+3)

Step-by-step explanation:

The first thing that I noticed was that all of the terms had a common factor of b^2. You can therefore factor that out first:

5x^2b^2 + 14xb^2 -3b^2= \\\\b^2(5x^2+14x-3)

Now, you have a quadratic equation inside the parentheses. Factoring, you find that the roots are -0.2 and 3, meaning that you can further factor this expression to be:

5b^2(x-0.2)(x+3)

Hope this helps!

3 0
2 years ago
Pls help this is pretty urgent
KIM [24]

Answer:

(a)  0

(b)  f(x) = g(x)

(c)  See below.

Step-by-step explanation:

Given rational function:

f(x)=\dfrac{x^2+2x+1}{x^2-1}

<u>Part (a)</u>

Factor the <u>numerator</u> and <u>denominator</u> of the given rational function:

\begin{aligned} \implies f(x) & = \dfrac{x^2+2x+1}{x^2-1} \\\\& = \dfrac{(x+1)^2}{(x+1)(x-1)}\\\\& = \dfrac{x+1}{x-1}\end{aligned}

Substitute x = -1 to find the limit:

\displaystyle \lim_{x \to -1}f(x)=\dfrac{-1+1}{-1-1}=\dfrac{0}{-2}=0

Therefore:

\displaystyle \lim_{x \to -1}f(x)=0

<u>Part (b)</u>

From part (a), we can see that the simplified function f(x) is the same as the given function g(x).  Therefore, f(x) = g(x).

<u>Part (c)</u>

As x = 1 is approached from the right side of 1, the numerator of the function is positive and approaches 2 whilst the denominator of the function is positive and gets smaller and smaller (approaching zero).  Therefore, the quotient approaches infinity.

\displaystyle \lim_{x \to 1^+} f(x)=\dfrac{\to 2^+}{\to 0^+}=\infty

5 0
1 year ago
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