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Luda [366]
3 years ago
13

Which situations shows a constant rate of change?

Mathematics
1 answer:
Schach [20]3 years ago
4 0

Answer:

A constant rate of change is accomplished when the change in one situation constantly results in changing another. In the scenario of a booster club constantly selling raffle tickets, the more tickets they sold the more the club raises.

Have an amazing day friend! <3

You might be interested in
What are the solutions of the equation x^4 + 6x^2 + 5 = 0? Use u substitution to solve.
Radda [10]

Answer:

second option

Step-by-step explanation:

Given

x^{4} + 6x² + 5 = 0

let u = x², then

u² + 6u + 5 = 0 ← in standard form

(u + 1)(u + 5) = 0 ← in factored form

Equate each factor to zero and solve for u

u + 1 = 0 ⇒ u = - 1

u + 5 = 0 ⇒ u = - 5

Change u back into terms of x, that is

x² = - 1 ( take the square root of both sides )

x = ± \sqrt{-1} = ± i ( noting that \sqrt{-1} = i ), and

x² = - 5 ( take the square root of both sides )

x = ± \sqrt{-5} = ± \sqrt{5(-1)} = ± \sqrt{5} × \sqrt{-1} = ± i\sqrt{5}

Solutions are x = ± i and x = ± i\sqrt{5}

3 0
3 years ago
I need the answer please
devlian [24]

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Answer:  x = 37

Explanation:

2x-5 + 3x = 180

5x - 5 = 180

5x = 185

x = 37

I hope this helped!

<!> Brainliest is appreciated! <!>

- Zack Slocum

*☆*――*☆*――*☆*――*☆*――*☆*――*☆*――*☆*――*☆**☆*――*☆*――*☆*――*☆

5 0
2 years ago
Read 2 more answers
Please Help Me Quickly As Soon As Possible, I Have A Test. I Will Give Out Brainly.
Dima020 [189]

The equation to show the depreciation at the end of x years is

f(x) = 1500 - 200x

Data;

  • cost of machine = 1500
  • annual depreciation value = x

<h3>Linear Equation</h3>

This is an equation written to represent a word problem into mathematical statement and this is easier to solve.

To write a linear depreciation model for this machine would be

For number of years, the cost of the machine would become

1500 - 200x

This is properly written as

f(x) = 1500 - 200x

where x represents the number of years.

For example, after 5 years, the value of the machine would become

f(x) = 1500 - 200x\\f(5) = 1500 - 200(5)\\f(5) = 1500 - 1000\\f(5) = 500

The value of the machine would be $500 at the end of the fifth year.

From the above, the equation to show the depreciation at the end of x years is f(x) = 1500 - 200x

Learn more on linear equations here;

brainly.com/question/4074386

8 0
2 years ago
A number h is at least -12
sasho [114]

Answer:

The at least sign is ≥. So, h ≥ -12

5 0
3 years ago
Which is greater or equal to 8/10 or 63/100
Elena L [17]
8/10 is greater than 63/100 because when 8/10 is turned into a percentage it is greater
8 0
3 years ago
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