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jeka94
2 years ago
12

Find the distance between the following points: (0,0,0) and (-2,6,3)

Mathematics
1 answer:
marusya05 [52]2 years ago
6 0

9514 1404 393

Answer:

  3.  7

Step-by-step explanation:

The distance formula applies in 3 dimensions as well as 2.

  d = √((x2 -x1)² +(y2 -y1)² +(z2 -z1)²)

  d = √((-2)² +6² +3²) = √(4 +36 +9) = √49

  d = 7

The distance between the two points is 7 units.

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After transforming f(x) = 2x² + 4x + 3 into vertex form, the vertex is easily identifiable. Which ordered pair is the vertex?
vagabundo [1.1K]

Answer:

The correct answer to your question is A because your asking for the vertex of the equation.

Step-by-step explanation:

Vertex                                                                                                                         Algebraic Equations

6 0
3 years ago
Please help me with this
zhannawk [14.2K]

Answer:  -6, -3, -2, -1, 1, 2, 3, 6

<u>Step-by-step explanation:</u>

NOTES: p is the last term, q is the coefficient of the first term

Determine all of the factors of p and all of the factors of q

Possible rational roots are all of the combinations of p/q for every factor

\dfrac{p}{q}=\pm \dfrac{6}{1}=\pm \dfrac{1\times 6, 2\times 3}{1}=\pm\dfrac{1}{1}, \pm\dfrac{6}{1}, \pm\dfrac{2}{1}, \pm\dfrac{3}{1}\\\\\\\text{In order from smallest to largest:}\ \large\boxed{-6, -3, -2, -1, +1, +2, +3, +6}

8 0
2 years ago
What is the greatest common<br>factor of the terms...​
Vika [28.1K]

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Step-by-step explanation:

8 0
3 years ago
Find the equation of the line that is parallel to x=6y-5 and that passes through (5,-3). express answer in standard form
Anestetic [448]

Answer:

Final answer is x-6y=23

Step-by-step explanation:

We need to find the equation of the line that is parallel to x=6y-5 and that passes through (5,-3).

So first we need to find the slope of given line.

rewirite x=6y-5 in y=mx+b form

x+5=6y

\frac{1}{6}x+\frac{5}{6}=y

Compare given equation with y=mx+b

we get: m=1/6

We know that parallel equations has equal slope.

Then slope of required line m=1/6

Now plug the given point (5,-3) and slope m=1/6 into point slope formula:

y-y_1=m\left(x-x_1\right)

y-(-3)=\frac{1}{6}\left(x-5\right)

y+3=\frac{1}{6}x-\frac{5}{6}

y=\frac{1}{6}x-\frac{5}{6}-3

y=\frac{1}{6}x-\frac{23}{6}

Now we need to rewrite that equation in standard form. Ax+By=C.

6y=x-23

x-23=6y

x-6y=23

Hence final answer is x-6y=23

6 0
3 years ago
I'm confused how you split the fraction
slava [35]
1/3 + 1/3 + 1/3 + 1/3 + 1/3 + 1/3 = 6/3 
8 0
3 years ago
Read 2 more answers
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