<h3>Answer: A. 5/12, 25/12</h3>
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Work Shown:
12*sin(2pi/5*x)+10 = 16
12*sin(2pi/5*x) = 16-10
12*sin(2pi/5*x) = 6
sin(2pi/5*x) = 6/12
sin(2pi/5*x) = 0.5
2pi/5*x = arcsin(0.5)
2pi/5*x = pi/6+2pi*n or 2pi/5*x = 5pi/6+2pi*n
2/5*x = 1/6+2*n or 2/5*x = 5/6+2*n
x = (5/2)*(1/6+2*n) or x = (5/2)*(5/6+2*n)
x = 5/12+5n or x = 25/12+5n
these equations form the set of all solutions. The n is any integer.
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The two smallest positive solutions occur when n = 0, so,
x = 5/12+5n or x = 25/12+5n
x = 5/12+5*0 or x = 25/12+5*0
x = 5/12 or x = 25/12
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Plugging either x value into the expression 12*sin(2pi/5*x)+10 should yield 16, which would confirm the two answers.
Answer:
60x+147
Step-by-step explanation:
10(6x+15)-3
60x+150-3
60x+147
Answer:
111 / 190
Step-by-step explanation:
Total biscuits = 20
Plain, P = 12
Chocolate, C = 5
Currant, K = 3
Assume without replacement :
Probability that biscuit are of the same type :
P(plain) :
12 / 20 * 11 / 19 = 132 / 380
P(chocolate) :
5/ 20 * 4 / 19 = 20/ 380
P(currant) :
3/20 * 2 /19 = 6 / 380
Therefore,
Probability that biscuit is of the same type :
P(plain) + P(chocolate) + P(currant)
132/380 + 20/380 + 6/380
158 / 380 = 79 / 190
Therefore, probability that biscuit aren't of the same type :
1 - P(biscuit is of same type)
1 - 79/190
(190 - 79) / 190
111 / 190
Answer:
what is the problem
Step-by-step explanation:
i need picture
Data? I need the data! Not trying to provoke, but in order to answer this I need data...