The Lesser Sooty Owl is a strictly nocturnal bird. Hides & sleeps during the day in dense foliage, between tangles of aerial roots, in all kinds of crevices, or beneath overhanging banks. Hunts in clearings and near roads, but also inside forest.
Answer:
Correct answer: Fourth answer As = 73.06 m²
Step-by-step explanation:
Given:
Radius of circle R = 16 m
Angle of circular section θ = π/2
The area of a segment is obtained by subtracting from the area of the circular section the area of an right-angled right triangle.
We calculate the circular section area using the formula:
Acs = R²· θ / 2
We calculate the area of an right-angled right triangle using the formula:
Art = R² / 2
The area of a segment is:
As = Acs - Art = R²· θ / 2 - R² / 2 = R² / 2 ( θ - 1)
As = 16² / 2 · ( π/2 - 1) = 256 / 2 · ( 1.570796 - 1) = 128 · 0.570796 = 73.06 m²
As = 73.06 m²
God is with you!!!
Answer:
This is 0.14 to the nearest hundredth
Step-by-step explanation:
Firstly we list the parameters;
Drive to school = 40
Take the bus = 50
Walk = 10
Sophomore = 30
Junior = 35
Senior = 35
Total number of students in sample is 100
Let W be the event that a student walked to school
So P(w) = 10/100 = 0.1
Let S be the event that a student is a senior
P(S) = 35/100 = 0.35
The probability we want to calculate can be said to be;
Probability that a student walked to school given that he is a senior
This can be represented and calculated as follows;
P( w| s) = P( w n s) / P(s)
w n s is the probability that a student walked to school and he is a senior
We need to know the number of seniors who walked to school
From the table, this is 5/100 = 0.05
So the Conditional probability is as follows;
P(W | S ) = 0.05/0.35 = 0.1429
To the nearest hundredth, that is 0.14
Answer:
24 ounce package ( cheapest )
Answer:
-1/3 < x <(or equal to) 2
Step-by-step explanation:
Firstly divide your inequality into two separate inequalities...
1) -1 < 6x + 1...then solve for the first one..,which then gives you....;
-2 < 6x....which gives us our first solution (x > -1/3)
Then the second inequality
2) 6x + 1 <(or equal to) 13
which then gives you....,
6x <(or equal to) 12...which then gives our second solution...( x <(or equal to) 2)
Then combine the two solutions into a compound solution
-1/3 < x <(or equal to) 2
