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3 years ago

What is y=10x+4/7 expressed in general form

Mathematics

2 answers:

Dmitry [639]3 years ago

4 0

Ten x plus four divided by seven

bonufazy [111]3 years ago

4 0

10x - y = -4/7 , would be the answer.

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Let Y be a random variable with a density function given by

Neporo4naja [7]

From the given density function we find the distribution function,

$F_Y(y)=P(Y\le y)=\displaystyle\int_{-\infty}^y f_Y(t)\,\mathrm dt=\begin{cases}0&\text{for }y$

(a)

$F_{U_1}(u_1)=P(U_1\le u_1)=P(3Y\le u_1)=P\left(Y\le\dfrac{u_1}3\right)=F_Y\left(\dfrac{u_1}3\right)$

$\implies F_{U_1}(u_1)=\begin{cases}0&\text{for }u_1$

$\implies f_{U_1}(u_1)=\begin{cases}\frac{{u_1}^2}{18}&\text{for }-3\le u_1\le3\\0&\text{otherwise}\end{cases}$

(b)

$F_{U_2}(u_2)=P(3-Y\le u_2)=P(Y\ge3-u_2)=1-P(Y$

$\implies F_{U_2}(u_2)=\begin{cases}0&\text{for }u_2$

$\implies f_{U_2}(u_2)=\begin{cases}\frac32(u_2-3)^2&\text{for }2\le u_2\le4\\0&\text{otherwise}\end{cases}$

(c)

$F_{U_3}(u_3)=P(Y^2\le u_3)=P(-\sqrt{u_3}\le Y\le\sqrt{u_3})=F_Y(\sqrt{u_3})-F_y(\sqrt{u_3})$

$\implies F_{U_3}(u_3)=\begin{cases}0&\text{for }u_3$

$\implies f_{U_3}(u_3}=\begin{cases}\frac32\sqrt u&\text{for }0\le u\le1\\0&\text{otherwise}\end{cases}$

5 0

3 years ago

How many positive integers are in the solution set of the inequality below? -2x + 1 ≥ -6

coldgirl [10]

Answer:

3 integers, with values: 1,2,3

Step-by-step explanation:

-2x+1>=-6

2x-1<=6

2x<=7

Positive integers: x=1,2,3

Count: 3

7 0

3 years ago

Read 2 more answers

Is 380 less than 248

Oliga [24]

Answer:

not unless its a negative integer

Step-by-step explanation:

380 is more than 248 but if 380 was put as a negative, it would be seenon the number line as less.

example: -380.......0........248

example 2: 0.....248.....380

8 0

3 years ago

pentru a asorta pernele cu sfoara, aura coase fiecareia , pe margini pamblica albastra. cati cm sunt necesari ? rezolva intrun s

lara [203]

I think the answer is 98352 cm.

6 0

3 years ago

Find the probability that in a pig family of 4 offspring there will be at least 1 male and 1 female. Assume that the probability

Naya [18.7K]

The probability of there being zero males is given by:
$P(zero\ males)=4C0\times0.5^{0}\times0.5^{4}=\frac{1}{16}$
Similarly the probability of there being zero females is also 1/16.
The probability there will be at least 1 male and 1 female is therefore:
$1-(\frac{1}{16}+\frac{1}{16})=\frac{7}{8}$
The answer is: 7/8.

5 0

3 years ago