Answer:
2196 fish
Step-by-step explanation:
Weight of fish that the killer whale might eat in a month (30 days) = 14,000 lb
Weight of the fish that killer whale might eat in a day = 
lb.
Average weight of the fish that killer whale eats = 3.4 oz
Since,
1 pound(lb) = 16 ounces(oz)
So,
Weight of the fish that killer whale might eat in a day in ounces(oz) = 
oz
Since, a certain fish weighs 3.4 oz, in order to find the number of fish that killer whale must eat, we must divide the total weight in ounces by 3.4 ounces.
So, the number of fish that killer whale would eat = 
fish
Thus, the killer whale needs to eat 2196 fish.
The answer is 10110
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Explanation:
Divide 22 over 2. Use long division to find the quotient and remainder
22/2 = 11 remainder 0 <<--- this remainder will be used later. Call it A, so A = 0
Now repeat for the value 11, which was the quotient above
11/2 = 5 remainder 1 <<--- this remainder will be used later. Call it B, so B = 1
Repeat again for the quotient we just got
5/2 = 2 remainder 1 <<--- this remainder will be used later. Call it C, so C = 1
Repeat again
2/2 = 1 remainder 0 <<--- this remainder will be used later. Call it D, so D = 0
Repeat again
1/2 = 0 remainder 1 <<--- this remainder will be used later. Call it E, so E = 1
The last quotient above is 0, so we stop here. If we tried to keep going, then we'd get nothing but 0 remainders forever.
The remainders we got above were:
A = 0
B = 1
C = 1
D = 0
E = 1
The idea is to read the remainders in reverse order in which we found. So we start with E and work back to A
E = 1
D = 0
C = 1
B = 1
A = 0
So 22 base 10 = 10110 base 2
Which situation could best be represented by the integer 120?
1. could be negative but the likely of losing 120 pounds is very low
2. this number would be positive
3. could be between -1 to - infinity
answer: 3. the number of feet below a surface
Correct answer is D).
A) and C) are polynomials, so x∈R, in B) we have √x, and in this case x ≥ 0.
