10 out of 10 equals 1.
then there is 9 left.
This gives 1 and 9 over 10.
9 over ten is not a whole number as 10 over ten is.
Hope this helps.
Answer:
ΔHFG≅ΔSUT
Step-by-step explanation:
You just have to match up the sides and the angle.It's easier to color code them.
For example:
Segment SU would be congruent with HF. (both would be blue, just example color)
Angle U is congruent to angle F (red)
UT congruent to FG (green)
Answer:
1250 p² x¹² y³z⁶m⁵
Step-by-step explanation:
5x²y³z⁵m²(-2p²m³zx⁴)(-5x²)³
5x²y³z⁵m²(-2p²m³zx⁴)(-125x⁶)
5x²y³z⁵m²(250p²m³zx¹⁰)
1250 p²x¹²y³z⁶m⁵
![\bf \begin{array}{llll} &[(-6,2),(2,3),(1,1),(-7,2),(4,2)]\\\\ inverse& [(2,-6),(3,2),(1,1),(2,-7),(2,4)] \end{array} \\\\\\ \textit{is the original a one-to-one?}\qquad \stackrel{rep eated~y-values}{(-6,\stackrel{\downarrow }{2}),(2,3),(1,1),(-7,\stackrel{\downarrow }{2}),(4,\stackrel{\downarrow }{2})}](https://tex.z-dn.net/?f=%5Cbf%20%5Cbegin%7Barray%7D%7Bllll%7D%0A%26%5B%28-6%2C2%29%2C%282%2C3%29%2C%281%2C1%29%2C%28-7%2C2%29%2C%284%2C2%29%5D%5C%5C%5C%5C%0Ainverse%26%20%5B%282%2C-6%29%2C%283%2C2%29%2C%281%2C1%29%2C%282%2C-7%29%2C%282%2C4%29%5D%0A%5Cend%7Barray%7D%0A%5C%5C%5C%5C%5C%5C%0A%5Ctextit%7Bis%20the%20original%20a%20one-to-one%3F%7D%5Cqquad%20%5Cstackrel%7Brep%20eated~y-values%7D%7B%28-6%2C%5Cstackrel%7B%5Cdownarrow%20%7D%7B2%7D%29%2C%282%2C3%29%2C%281%2C1%29%2C%28-7%2C%5Cstackrel%7B%5Cdownarrow%20%7D%7B2%7D%29%2C%284%2C%5Cstackrel%7B%5Cdownarrow%20%7D%7B2%7D%29%7D)
notice, the inverse set is just, the same set with the x,y turned to y,x, backwards.
is it a one-to-one? well, for a set to be a one-to-one, it must not have any x-repeats, that is, the value of the first in the pairs must not repeat, and it also must not have any y-repeats, namely the value of the second in the pairs must not repeat.
Answer:
the answer is c. Have a nice day!!
