Answer: a) √50
b) n = 1 + 7i
Step-by-step explanation:
first, the modulus of a complex number z = a + bi is
IzI = √(a^2 + b^2)
The fact that n is complex does not mean that n doesn't has a real part, so we must write our numbers as:
m = 2 + 6i
n = a + bi
Im + nI = 3√10
Im + n I = √(a^2 + b^2 + 2^2 + 6^2)= 3√10
= √(a^2 + b^2 + 40) = 3√10
a^2 + b^2 + 40 = 3^2*10 = 9*10 = 90
a^2 + b^2 = 90 - 40 = 50
√(a^2 + b^2 ) = InI = √50
The modulus of n must be equal to the square root of 50.
now we can find any values a and b such a^2 + b^2 = 50.
for example, a = 1 and b = 7
1^2 + 7^2 = 1 + 49 = 50
Then a possible value for n is:
n = 1 + 7i
Answer:
3^(n+1) - 3^n / 3^(n-1) = 6
U r going to subtract 3 from each side of the equation....leaving you with :
x^2 + 2x = -3
At first find the area of rectangle:
(x + 4)*(x + 1) = x^2 + 5x + 4
Then find the area of triangle:
Then you must do like this
Area of rectangle - Area of triangle = Area of the shaded
x^2+5x+4 - (
)
Answer:
I cant really see any answer but if I had to simplify, then the answer would be 2t - 8 + 1, which would then be simplified to 2t - 7.
Have a nice and wonderfull day.
Brainliest would be appreciated.
Step-by-step explanation:
