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Serhud [2]
2 years ago
6

Can someone plss help ASAP

Mathematics
1 answer:
Elza [17]2 years ago
4 0

Answer:

8.2.69 ≤ x ≤ 17.31

11. x-7.31 ≤ 10

12. x≤17.31

Let the amount in the other Piggybank be x.

If positive;

x-7.31 ≤ 10

x ≤ 10+7.31

x ≤ 17.31

If negative

-(x-7.31) ≤ 10

-x+7.31 ≤ 10

-x ≤ 10-7.31

-x ≤ 2.69

Multiply both sides by -1

x ≥ -2.69

The compound inequality representing the amount of money in the other bank is -2.69≤x≤17.31

Step-by-step explanation:

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Evaluate the expression.
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Answer:

17

Step-by-step explanation:

2 sqrt(81) -1

We know the sqrt(81) = 9

2*9 -1

18-1

17

7 0
3 years ago
Given f: ℝ → ℝ and : ℝ → ℝ , for the following, find f(g(x)) and g(f(x)), and state the domain.
horrorfan [7]

Answer:

Remember, (f\circ g)(x)=f(g(x)) and the range of g must be in the domain of f.

a)

f(g(x))=f(x-1)=(x-1)^2-(x-1)=x^2-2x+1-x+1=x^2-3x+2

g(f(x))=g(x^2-x)=(x^2-x)-1=x^2-x-1

The domain of f(g(x)) and g(f(x)) is the set of reals.

b)

f(g(x))=f(\sqrt{x}-2)=(\sqrt{x}-2)^2-x=\sqrt{x}^2-2*2*\sqrt{x}+2^2-x=-4\sqrt{x}+4

g(f(x))=g(x^2-x)=\sqrt{x^2-x}-2

The domain of f(g(x)) is the set of nonnegative reals and the domain of g(f(x)) is the set of number such that x^2-x\geq 0

c)

f(g(x))=f(\frac{1}{x-1})=(\frac{1}{x-1})^2=\frac{1}{(x-1)^2}

g(f(x))=g(x^2)=\frac{1}{x^2-1}

The domain of f(g(x)) is the set of reals except the 1 and the domain of g(f(x)) is the set of reals except the 1 and -1

d)

f(g(x))=f(\frac{1}{x-1})=\frac{1}{(\frac{1}{x-1}-1)}=\frac{1}{\frac{2-x}{x-1}}=\frac{x-1}{2-x}

g(f(x))=g(\frac{1}{x+2})=\frac{1}{(\frac{1}{x+2}-1)}=\frac{1}{\frac{-x-1}{x+2}}=\frac{x+2}{-x-1}

The domain of f(g(x)) is the set of reals except 2, and the domain of g(f(x)) is the set of reals except -1.

e)

f(g(x))=f(log(2(x+3)))=f(log(2x+6))=log(2x+6)-1

g(f(x))=g(x-1)=log(2(x-1)+6)=log(2x+4)

The domain of f(g(x)) is the set of nonnegative reals except -3. The domain of g(f(x)) is the set of nonnegative reals except -2.

3 0
3 years ago
Help me guys...:(<br>prove that 0!=1<br><br>​
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Answer:

0 + 1=0

hope this helps

have a good day :)

Step-by-step explanation:

6 0
3 years ago
The length of a room is 20 feet and its width is 12 feet. Whats the perimeter
Tems11 [23]
Perimeter = 2 x Length + 2 x Width

Perimeter = 2(20) + 2(12) = 64 feet.

------------------------------------------
Answer: Perimeter = 64 feet.
------------------------------------------
4 0
3 years ago
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