If you would like to know which lists all the integer solutions of the inequality <span>|x| < 3, you can calculate this using the following steps:
</span><span>|x| < 3
- 3 < x < 3
x = {-2, -1, 0, 1, 2}
The correct result would be C. -2, -1, 0, 1, and 2.</span>
The answer to this question would be: p+q+r = 2 + 17 + 39= 58
In this question, p q r is a prime number. Most of the prime number is an odd number. If p q r all odd number, it wouldn't be possible to get 73 since
odd x odd + odd= odd + odd = even
Since 73 is an odd number, it is clear that one of the p q r needs to be an even number.
There is only one odd prime number which is 2. If you put 2 in the r the result would be:
pq+2= 73
pq= 71
There will be no solution for pq since 71 is prime number. That mean 2 must be either p or q. Let say that 2 is p, then the equation would be: 2q + r= 73
The least possible value of p+q+r would be achieved by founding the highest q since its coefficient is 2 times r. Maximum q would be 73/2= 36.5 so you can try backward from that. Since q= 31, q=29, q=23 and q=19 wouldn't result in a prime number r, the least result would be q=17
r= 73-2q
r= 73- 2(17)
r= 73-34=39
p+q+r = 2 + 17 + 39= 58
58 degrees
Explanation
If you have a triangle with the angle measures of abc as 58 degrees, 102 degrees and 20 degrees you can multiply them in order of abc so 58 degrees is angle a, 102 degrees is angle b and 20 degrees is angle c. Then you just put in angle a for d which would be 58 degrees and angle e for b 102 degrees and angle f for c which would be 20 degrees
