Plsss help!!!!!!!!!!!

Combine the like terms to create an equivalent expression:

Nesterboy [21]

Answer:

-2z+8

Step-by-step explanation:

$3z+2+(-5x)+6\\\\=3z+2-5x+6\\\\=(3z-5z)+(2+6)\\\\=(-2z)+(8)\\\\=-2z+8$

6 0

3 years ago

PLEASEEE HELP !!

miss Akunina [59]

Answer: b+95+34=180, b+129=180, 51

Step-by-step explanation:

b+95+34=180 works because the angles add to form a straight angle.

From this, we can obtain b+129=180 by adding the two constants.

Subtracting 129 from both sides, we get b=51.

6 0

2 years ago

A hiker travels 45 degrees north of east for 30 km. What is his NORTH (or y) displacement component? Round your answer and inclu

miv72 [106K]

consider X-axis along the east-west direction and north-south direction along Y-axis

A = magnitude of distance traveled by hiker in north-east direction = 30 kilometer

θ = angle of direction of displacement of the hiker relative to x-axis or east direction = 45 degree counterclockwise

A' = component of distance traveled by the hiker along the east direction.

Since the angle is given with the x-axis, the Sin provides the component in Y-direction. hence

Using the equation

A' = A Sinθ

Inserting the values

A' = (30) Sin45

A' = 21.2 km

8 0

3 years ago

Verify that the points are the vertices of a parallelogram and find its area. (2,-1,1), (5, 1,4), (0,1,1), (3,3,4)

Gelneren [198K]

Answer:

Area = 13.15 square units

Step-by-step explanation:

Let the given vertices be represented as follows:

A(2, -1, 1) = 2i - j + k

B(5, 1, 4) = 5i + j + 4k

C(0, 1, 1) = 0i + j + k

D(3, 3, 4) = 3i + 3j + 4k

(i) Let's calculate the vectors of all the sides:

$\\$ AB = B - A = (5i + j + 4k) - (2i - j + k)

AB = 5i + j + 4k - 2i + j - k [Collect like terms]

AB = 3i + 2j + 3k

BC = C - B = (0i + j + k) - (5i + j + 4k)

BC = 0i + j + k - 5i - j - 4k [Collect like terms]

BC = -5i + 0j - 3k

CD = D - C = (3i + 3j + 4k) - (0i + j + k)

CD = 3i + 3j + 4k - 0i - j - k [Collect like terms]

CD = 3i + 2j + 3k

DA = A - D = (2i - j + k) - (3i + 3j + 4k)

DA = 2i - j + k - 3i - 3j - 4k [Collect like terms]

DA = -i - 4j - 3k

AC = C - A = (0i + j + k) - (2i - j + k)

AC = 0i + j + k - 2i + j - k [Collect like terms]

AC = -2i + 2j

BD = D - B = (3i + 3j + 4k) - (5i + j + 4k)

BD = 3i + 3j + 4k - 5i - j - 4k [Collect like terms]

BD = -2i + 2j

(ii) From the results in (i) above, we can deduce that;

AB = CD This implies that AB || CD [AB is parallel to CD]

AC = BD This implies that AC || BD [AC is parallel to BD]

(iii) Therefore, ABDC is a parallelogram since opposite sides (AB and CD) are parallel. Hence, the points are vertices of a parallelogram

Now let's calculate the area

To find the area of the parallelogram, we find the magnitude of the cross product of any two adjacent sides.

In this case, we'll choose AB and AC

Area = |AB X AC|

Where;

$AB X AC = \left[\begin{array}{ccc}i&j&k\\3&2&3\\-2&2&0\end{array}\right]$

AB X AC = i(0 - 6) - j(0 + 6) + k(6 + 4)

AB X AC = - 6i - 6j + 10k

|AB X AC| = $\sqrt{(-6)^2 + (-6)^2 + (10)^2}$

|AB X AC| = $\sqrt{172}$

|AB X AC| = 13.15

Area = 13.15 square units.

PS: ACBD is also a parallelogram. The diagram has also been attached to this response.

6 0

3 years ago

Complete the square and graph: 9y²−x − 18y +10=0

Nitella [24]

Answer:

See below ~

Step-by-step explanation:

Completing the square :

9y² - x - 18y + 10 = 0
9y² - 18y + 9 - 9 - x + 10 = 0
(3y - 3)² - x + 1 = 0

Graph :

4 0

2 years ago

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