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4 years ago

Write an expression for the calculation 2/3 times the sum of 2/8 and 4/8

Mathematics

1 answer:

zubka84 [21]4 years ago

5 0

2/3(2/8 + 4/8) = 2/3(1/4 + 1/2)
2/3(3/4) = 1/2

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How many minutes equal 5.4 days? a. 7776 b. 1440 c. 1296 d. 3888

Mazyrski [523]

Hello,

Shall we begin?

Minutes of hour = 60
Hours per day = 24
Days = 5.4

= 24 * 60 * 5.4
= 7,776

Answers: a) 7,776

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3 years ago

What is commutative property in rational number ? please explain.

slavikrds [6]

Answer:

Commutative property of addition of rational numbers: Two rational numbers can be added in any order. Thus for any two rational numbers a/b and c/d, we have. (a/b + c/d) = (c/d + a/b)

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3 years ago

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Alexus [3.1K]

Answer:

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Step-by-step explanation:

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3 years ago

Naval intelligence reports that 4 enemy vessels in a fleet of 17 are carrying nuclear weapons. If 9 vessels are randomly targete

icang [17]

Answer:

0.7588 = 75.88% probability that more than 1 vessel transporting nuclear weapons was destroyed

Step-by-step explanation:

The vessels are destroyed without replacement, which means that the hypergeometric distribution is used to solve this question.

Hypergeometric distribution:

The probability of x successes is given by the following formula:

$P(X = x) = h(x,N,n,k) = \frac{C_{k,x}*C_{N-k,n-x}}{C_{N,n}}$

In which:

x is the number of successes.

N is the size of the population.

n is the size of the sample.

k is the total number of desired outcomes.

Combinations formula:

$C_{n,x}$ is the number of different combinations of x objects from a set of n elements, given by the following formula.

$C_{n,x} = \frac{n!}{x!(n-x)!}$

In this question:

Fleet of 17 means that $N = 17$

4 are carrying nucleas weapons, which means that $k = 4$

9 are destroyed, which means that $n = 9$

What is the probability that more than 1 vessel transporting nuclear weapons was destroyed?

This is:

$P(X > 1) = 1 - P(X \leq 1)$

In which

$P(X \leq 1) = P(X = 0) + P(X = 1)$

$P(X = x) = h(x,N,n,k) = \frac{C_{k,x}*C_{N-k,n-x}}{C_{N,n}}$

$P(X = 0) = h(0,17,9,4) = \frac{C_{4,0}*C_{13,9}}{C_{17,9}} = 0.0294$

$P(X = 1) = h(1,17,9,4) = \frac{C_{4,1}*C_{13,8}}{C_{17,9}} = 0.2118$

Then

$P(X \leq 1) = P(X = 0) + P(X = 1) = 0.0294 + 0.2118 = 0.2412$

$P(X > 1) = 1 - P(X \leq 1) = 1 - 0.2412 = 0.7588$

0.7588 = 75.88% probability that more than 1 vessel transporting nuclear weapons was destroyed

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3 years ago

What is the value of this expression? 42+3×5−(15−3×6)2 4 2 + 3 × 5 − ( 15 − 3 × 6 ) 2

kenny6666 [7]

The solution is the B. 22

6 0

3 years ago

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