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Elza [17]
3 years ago
8

Solve for x in the equation x squared minus 12 x + 36 = 90.

Mathematics
2 answers:
olasank [31]3 years ago
7 0

Answer:

A on edge

Step-by-step explanation:

ValentinkaMS [17]3 years ago
6 0

Answer:

a

Step-by-step explanation:

edge 2021

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Factorise fully 77x-33x^2
lesya [120]

Answer:

11x(7 - 3x)

Step-by-step explanation:

77x - 33x² ← factor out 11x from each term

= 11x(7 - 3x)

7 0
2 years ago
At a local fitness center members pay a a $ 14 membership fee and $ 2 for each aerobics class. Nonmembers pay $ 4 for each aerob
mestny [16]

14+2x=4x: divide 2x on each side

14=2x: divide by 2

7=x

7

8 0
3 years ago
Alyssa takes part in the triathlon. She cycles 4/5 of the route, runs 7/8 of the route, and swims the rest of the way. She swims
hjlf

Answer:

12 miles

Step-by-step explanation:

Alyssa takes part in the triathlon. She cycles 4/5 of the route, runs 1/8 of the route, and swims the rest of the way. She swims 0.9 miles. Find the total distance of the triathlon route.

Total distance Alyssa cycled and ran =

\frac{4}{5} + \frac{1}{8}

\frac{32 + 5}{40} = \frac{37}{40}

Distance she swam =  1 - 37/40 = 3/40

3/40 of the distance is 0.9

the total distance = 40/3 x 0.9 = 12 miles

3 0
2 years ago
I need help with this assignment.
Gelneren [198K]
2. Definition of supplementary angles
I’m not too good with proofs but hopefully at least one answer helped lol sorry
8 0
3 years ago
Discuss the continuity of the function on the closed interval.Function Intervalf(x) = 9 − x, x ≤ 09 + 12x, x > 0 [−4, 5]The f
quester [9]

Answer:

It is continuous since \lim_{x\to 0^{-}} = f(0) = \lim_{x \to 0^{+} f(x)

Step-by-step explanation:

We are given that the function is defined as follows f(x) = 9-x, x\leq 0 and f(x) = 9+12x, x>0 and we want to check the continuity in the interval [-4,5]. Note that this a piecewise function whose only critical point (that might be a candidate of a discontinuity)  x=0 since at this point is where the function "changes" of definition. Note that 9-x and 9+12x are polynomials that are continous over all \mathbb{R}. So F is continous in the intervals [-4,0) and (0,5]. To check if f(x) is continuous at 0, we must check that

\lim_{x\to 0^{-}} = f(0) = \lim_{x \to 0^{+} f(x) (this is the definition of continuity at x=0)

Note that if x=0, then f(x) = 9-x. So, f(0)=9. On the same time, note that

\lim_{x\to 0^{-}} f(x) = \lim_{x\to 0^{-}} 9-x = 9. This result is because the function 9-x is continous at x=0, so the left-hand limit is equal to the value of the function at 0.

Note that when x>0, we have that f(x) = 9+12x. In this case, we have that

\lim_{x\to 0^{+}} f(x) = \lim_{x\to 0^{+}} 9+12x = 9. As before, this result is because the function 9+12x is continous at x=0, so the right-hand limit is equal to the value of the function at 0.

Thus, \lim_{x\to 0^{-}} = f(0) = \lim_{x \to 0^{+} f(x)=9, so by definition, f is continuous at x=0, hence continuous over the interval [-4,5].

5 0
3 years ago
Read 2 more answers
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